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vodka [1.7K]
3 years ago
9

I'm studying for a test and got stuck on this problem. I took a screenshot !! Please help. I just need part C for number 5, I ge

t everything else

Mathematics
1 answer:
Studentka2010 [4]3 years ago
8 0
Alright, so for AB and CD to be parallel, CX and DX would have to be equal, as is with AX and BX. In addition, for CD and AB to be parallel, all sides in both triangles are either equal or not all sides in even one triangle are equal. Therefore, CD is not 3. In addition, two sides of a triangle combined must be greater than the third, so that leaves 5, 4, and 2 for CD. If it was 5, that would mean that all sides are equal, so that leaves 4 and 2. However, I don't see anything to prove either one right, sorry:/
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There are 99 males and 121 females participating in a marathon. What percent of the participants are female?​
ioda

To do this, we first want to see how many participants there are in total by adding both males and females.

99+121=220

Now we know that there were 220 total participants, but only 121 were females.

This allows us to set up the fraction 121/220= the percent female.

\frac{121}{220} =0.55

or 55%

8 0
3 years ago
Jane has to stickers /
dimulka [17.4K]

Answer:

Andy basically has two stickers

4 0
2 years ago
The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.4 minutes and a standard deviation of 3.5
Lorico [155]

Answer:

0.6672 is the required probability.            

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8.4 minutes

Standard Deviation, σ = 3.5 minutes

We are given that the distribution of distribution of taxi and takeoff times is a bell shaped distribution that is a normal distribution.

According to central limit theorem the sum measurement of n is normal with mean \mu and standard deviation \sigma\sqrt{n}

Sample size, n = 37

Standard Deviation =

=\sigma\times \sqrt{n} = 3.5\times \sqrt{37}=21.28

P(taxi and takeoff time will be less than 320 minutes)

P( \sum x < 320) = P( z < \displaystyle\frac{320 - 37(8.4)}{21.28}) = P(z < 0.4323)

Calculation the value from standard normal z table, we have,  

P(\sum x < 320) =0.6672 = 66.72\%

0.6672 is the probability  that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

7 0
3 years ago
Find the distance between points B and N.
Gekata [30.6K]

Answer:

5

Step-by-step explanation:

b is at 15

n is at 10

hence -15 - -10=5

positive 5 btw

5 0
2 years ago
The sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab 2. if one addend is –5a2b2 12a2b – 5, what is the other addend? 15a2b2 –
Brrunno [24]

The other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

<h3>What is polynomial?</h3>

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is real number).

The sum of two polynomials is,

10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2

The one polynomial addend is,

-5a^2b^2 +12a^2b - 5

Let suppose the other polynomial addend is f(a,b). Thus,

(-5a^2b^2 +12a^2b - 5)+f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)

Isolate the second polynomial as,

f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)-(-5a^2b^2 +12a^2b - 5)\\f(a,b)=10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2+5a^2b^2 -12a^2b + 5

Arrange the like terms as,

f(a,b)=10a^2b^2+5a^2b^2 - 8a^2b -12a^2b+ 6ab^2 - 4ab + 2+5\\f(a,b)=15a^2b^2- 20a^2b + 6ab^2 - 4ab + 7

Hence, the other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

Learn more about polynomial here;

brainly.com/question/24380382

7 0
2 years ago
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