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vodka [1.7K]
3 years ago
9

I'm studying for a test and got stuck on this problem. I took a screenshot !! Please help. I just need part C for number 5, I ge

t everything else

Mathematics
1 answer:
Studentka2010 [4]3 years ago
8 0
Alright, so for AB and CD to be parallel, CX and DX would have to be equal, as is with AX and BX. In addition, for CD and AB to be parallel, all sides in both triangles are either equal or not all sides in even one triangle are equal. Therefore, CD is not 3. In addition, two sides of a triangle combined must be greater than the third, so that leaves 5, 4, and 2 for CD. If it was 5, that would mean that all sides are equal, so that leaves 4 and 2. However, I don't see anything to prove either one right, sorry:/
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Jennie makes quilts. She can make 7 quilts with 21 yards of material. How many yards of material would be required to make 12 qu
nlexa [21]
\frac{7}{21} = \frac{12}{yards}  \\  \\ 7*yards=21*12 \\  \\ 7yards=252 \\  \\ yards=36
4 0
4 years ago
Read 2 more answers
A) Find the distance of line segment PR. Round answer to the nearest tenth. B) Find the distance around the park (perimeter).
juin [17]

Answer:

A. PR = 80.6 yd

B. Perimeter = 190.6 yd

Step-by-step explanation:

A. Distance between P(10, 50) and R(80, 10):

PR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

PR = \sqrt{(80 - 10)^2 + (10 - 50)^2}

PR = \sqrt{(70)^2 + (-40)^2}

PR = \sqrt{4,900 + 1,600}

PR = \sqrt{6,500}

PR = 80.6 yd (nearest tenth)

B. Distance around the park = Perimeter = PR + PQ + QR

PR = 80.6 yd

PQ = |50 - 10| = 40 yd

QR = |80 - 10| = 70 yd

Perimeter = 80.6 + 40 + 70

Perimeter = 190.6 yd

7 0
3 years ago
Natasha is 12 years old. Her teacher is 36 years old. Which ratio represents Natasha's age in 4 years to her teacher's age in 4
Ainat [17]

Answer:

I’m pretty sure it’s 1:3

Step-by-step explanation:

5 0
3 years ago
A convex figure has three sides what is the sum of its exterior angles
SashulF [63]

A convex figure with three sides is triangle. The sum of the measures of all interior angles of the triangle is 180°.

Let \alpha, \beta, \gamma be interior angles of this triangle. Then

\alpha+\beta+\gamma=180^{\circ}.

Find exterior angles of this triangle:

1. 180^{\circ}-\alpha is exterior angle adjacent to the interior angle \alpha.

2. 180^{\circ}-\beta is exterior angle adjacent to the interior angle \beta.

3. 180^{\circ}-\gamma is exterior angle adjacent to the interior angle \gamma.

The sum of the measures of all exterior angles is

180^{\circ}-\alpha+180^{\circ}-\beta+180^{\circ}-\gamma=540^{\circ}-(\alpha+\beta+\gamma)=540^{\circ}-180^{\circ}=360^{\circ}.

Answer: 360°

4 0
3 years ago
Which triangle congruence theorem can be used to prove the triangles are congruent
Trava [24]

Answer:

SSS triangle congruence theorem

explanation:

If three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent.

7 0
3 years ago
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