Answer:
Step-by-step explanation:
Divide each term by - 1/4 first
- -1/2x ÷ (- 1/4) = 1/2x × 4 = 2x
- -5/4y ÷ (- 1/4) = 5/4y × 4 = 5y
Now facor out - 1/4
- - 1/2x - 5/4y =
- - 1/4 (2x + 5y)
Answer:The right answer is (B)
Step-by-step explanation:
Your welcome
Answer:
Step-by-step explanation:x+y+z=100(let x ,y,z represent the first second and third numbers respectively)
Therefore,y=2z
z=x-8
y=2x-16
substituting the values of x,y and z into the question,we have
x+(2x-16)+(x-8)=100
Simplifying,we have
4x-24=100
adding 24 to both sides of the equation,
4x=100+24
4x=124
dividing both sides of the equation by the co-efficient of x,we have
4x/4=124/4
4.31=124
therefore,x=31.
Answer:
the points are (35,30) you may need to search a graph online i used desmos
Step-by-step explanation:
1. x= Jacksons Cups y= Lucius Cups2. x - y= 5 6x + 3y = 300Substitution: 6 (y+5) + 3y = 300 6y + 30 + 3y = 300 9y = 270 dived both by 9 y=30 Sub y for other equation x - 30 = 5 add 30 to both sides x = 35 Answer: (35, 30) Graphing: x- y = 56x+ 3y = 300solve both for y y = x-5 6x + 3y = 300minus 6x from both sides the points are in y = mx + b y= 1x -5 y= -2x + 100 I will also leave the ss of the graph in the comments if you cannot see it My labels for the x-axis is Jacksons cups and y Is luscious cups. Elimination:x - y = 5 6x + 3y = 300 First I manipulated the equations by the following - 6 (x - y = 5 ) 1(6x + 3y = 300 ) -6x + 6y = -30 6x + 3y = 300 The 6 x's cancel and add the y's and real numbers together 9y = 270 dived both by 9 y= 30 Sub y for other equation x - 30 = 6 add 30 to both sides x= 30 The points are (35, 30) The solution is (35,30)They represent how many cups they sold. 35 is Jackson cups and 30 is Lucious's cups
Answer:
Interval [16.34 , 21.43]
Step-by-step explanation:
First step. <u>Calculate the mean</u>
Second step. <u>Calculate the standard deviation</u>
As the number of data is less than 30, we must use the t-table to find the interval of confidence.
We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).
We must then choose t = 1.476 (see attachment)
Now, we use the formula that gives us the end points of the required interval
where n is the number of observations.
The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43
