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BabaBlast [244]
3 years ago
11

A sandwich costs $0.75 more than a container of milk. A customer buys 4 sandwiches and 4 containers of milk. The customer pays $

7.00.
What is the cost of a sandwich?
Mathematics
1 answer:
Step2247 [10]3 years ago
8 0
Assume that the cost of the milk is x.
We are given that a sandwich costs 0.75$ more than the cost of milk. This means that:
cost of sandwich = cost of milk + 0.75
cost of sandwich = x + 0.75

Now, the customer bought 4 sandwiches and 4 containers of milk at the cost of 7$.
We will transform this into an equation as follows:
total cost = cost of 4 sandwiches + cost of 4 containers of milk
7 = 4(x+0.75) + 4(x)

Solve the above equation to get x as follows:
7 = 4x + 3 + 4x
7-3 = 8x
8x = 4
x = 0.5

Therefore:
cost of milk = x = $0.5
cost of sandwich = x+0.75 = 0.5+0.75 = $1.25
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Answer:

D = 4, Z = 24

Step-by-step explanation:

6D+3Z = 96

5D+4Z = 116

multiply top by 5 and bottom by -6

top equation = 30D+15Z = 480

bottom equation = -30D-24Z = -696

Cancel 30D and -30 D

top equation  = 15Z = 480

Bottom equation = -24Z = -696

15Z - 24 Z = 480 - 696

-9Z = 216

Z = 216/9

Z = 24

Now that we have the value of Z, we can substitute it in any equation to find D

6D + 3(24) = 96

6D + 72 = 96

6D = 96 - 72

6D = 24

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3 years ago
Halla la tasa de variación de cada funcion en el intervalo [-4,3] e indica si es positiva , negativa o nula A) f(x)=x2-2x+4 B) f
masya89 [10]

Answer:

A) \hspace{3}Rate\hspace{3}of\hspace{3}change=-5\hspace{3}Negative\\\\B)\hspace{3}Rate\hspace{3}of\hspace{3}change=-21\hspace{3}Negative  

Step-by-step explanation:

Given a function f(x), we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value "x_1" to another "x_2".

The rate of change of f(x) between x_1 and x_2 can be calculated as follows:

Rate\hspace{3}of\hspace{3}change=f(x_2)-f(x_1)

For:

f(x)=x^2-2x+4

Let's find f(x_1) and f(x_2), where:

[x_1,x_2]=[-4,3]

f(x_1)=f(-4)=(-4)^2-2(4)+4=16-8+4=12\\f(x_2)=f(3)=(3)^2-2(3)+4=9-6+4=7

So:

Rate\hspace{3}of\hspace{3}change =7-12=-5\hspace{3}Negative

And for:

f(x)-3x+2

Let's find f(x_1) and f(x_2), where:

[x_1,x_2]=[-4,3]

f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7

So:

Rate\hspace{3}of\hspace{3}change =-7-14=-21\hspace{3}Negative

<em>Translation:</em>

Dada una función f(x), llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor "x_1" a otro "x_2".

La tasa de variación de f(x) entre x_1 y x_2, puede ser calculada de la siguiente forma:

Tasa\hspace{3}de\hspace{3}variacion=f(x_2)-f(x_1)

Para:

f(x)=x^2-2x+4

Encontremos f(x_1) y f(x_2), donde:

[x_1,x_2]=[-4,3]

f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7

Entonces:

Tasa\hspace{3}de\hspace{3}variacion =7-12=-5\hspace{3}Negativa

Y para:

f(x)-3x+2

Encontremos f(x_1) y f(x_2), donde:

[x_1,x_2]=[-4,3]

f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7

Entonces:

Tasa\hspace{3}de\hspace{3}variacion=-7-14=-21\hspace{3}Negativa

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