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Readme [11.4K]
3 years ago
9

What is the equation of the midline for the function f(x) ?

Mathematics
1 answer:
ira [324]3 years ago
6 0

Answer:

<u><em>Y =0</em></u>

Step-by-step explanation:

<u><em>The midline is the y value that runs straight through the middle of the wave. If you can picture the standard sine function graph. f(x) = Sin(x) reaches a maximum y = 1 and minimum y = -1 so the midline is y =0.</em></u>

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Find the area of the shape below please. (:
e-lub [12.9K]

Answer:

105

Step-by-step explanation:

15*6=90

6*5=30

30/2=15

90+15=105

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
Simplify each write as a smaller fractions or mixed number 6 / 18
miv72 [106K]
6/18= 1/3 a simplest fraction
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Simply this expression. Which like terms can she combine 12-4x+3
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like terms include terms that you can add/sub/mult/div - certain terms..

for example 23 and 7 are like terms, 4x and 56x are like terms....


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12 + 3 - 4x

then you can simplify it:

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3 years ago
An integer N is to be selected at random from {1, 2, ... , (10)3 } in the sense that each integer has the same probability of be
Andrej [43]

Answer:

Probability of N Divisible by 3 - 0.33

Probability of N Divisible by 5 - 0.2

Probability of N Divisible by 7 - 0.413

Probability of N Divisible by 15 - 0.066

Probability of N Divisible by 105 - 0.0095

Step-by-step explanation:

Given data:

Integer N {1,2,.....10^3}

Thus total number of ways by which 1000 is divisible by 3 i.e. 1000/3 = 333.3

Probability of N divisible by 3 {N%3 = 0 } = \frac{333.3}{1000} = 0.33

total number of ways by which 1000 is divisible by 5 i.e. 1000/5 = 200

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total number of ways by which 1000 is divisible by 7 i.e. 1000/7 = 142.857

Probability of N divisible by 7 {N%7 = 0 } = \frac{142.857}{1000} = 0.413

total number of ways by which 1000 is divisible by 15 i.e. 1000/15 = 66.667

Probability of N divisible by 15 {N%15 = 0 } = \frac{66.667}{1000} = 0.066

total number of ways by which 1000 is divisible by 105 i.e. 1000/105 = 9.52

Probability of N divisible by 105 {N%105 = 0 } = \frac{9.52}{1000} = 0.0095

similarly for N is selected from 1,2.....(10)^k where K is  large then the N value. Therefore effect of k will remain same as previous part.

3 0
3 years ago
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