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4 years ago

What is the equation of the midline for the function f(x) ?

Mathematics

1 answer:

ira [324]4 years ago

6 0

Answer:

Y =0

Step-by-step explanation:

The midline is the y value that runs straight through the middle of the wave. If you can picture the standard sine function graph. f(x) = Sin(x) reaches a maximum y = 1 and minimum y = -1 so the midline is y =0.

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How much of the circle is shaded? Write your answer as a fraction in simplest form. 1/3 and 1/7

Ludmilka [50]

Answer:

11/21

Step-by-step explanation:

1/3=7/21

1/7=3/21

(7+3)/21=10/21

21/21-10/21=11/21

Thus 11/21 of the circle is shaded.

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3 years ago

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AfilCa [17]

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3 years ago

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mamaluj [8]

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3 years ago

98464 rounded to the nearest ten thousand?

dusya [7]

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Step-by-step explanation:

4 0

4 years ago

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F(t)=t^2+19t+60 What are the zeros of the function and what is the vertex of the parabola?

SVEN [57.7K]

Answer: $-4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

Step-by-step explanation:

Given

Function is $F(t)=t^2+19+60$

Zeroes of the function are

$t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15$

Using completing the square method

$y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

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3 years ago