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Kitty [74]
2 years ago
5

Write a break-even problem and use a system of linear equations to solve it.

Mathematics
1 answer:
Kipish [7]2 years ago
8 0
Sup Dixie I n d d d d d d did d s s did s s Dad d did d d d did did d d d d d
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The diagram is a straightedge and compass construction. A is the center of one circle,
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All the points are the same distance from the center of line AB, therefore it is just the same triangle but rotated. They are the same triangle .

Step-by-step explanation:

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3 years ago
Simplify the following expression:<br> 3X(4-1) + (6+21)
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Answer:

9x+27

Step-by-step explanation:

3x(4−1)+6+21

=9x+6+21

Combine Like Terms

=9x+6+21

=(9x)+(6+21)

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A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard
bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44

In point a)  

\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}

  = \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2

value= (1- \frac{1}{k^2}) \times 100 \% =75\%

In point b)

\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma  \\\\= |(x-\mu)|\leq 2.5 \times 4.44  \\\\  = |(x-\mu)|\leq 1.11 \\\\ =  (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)

In point c)

\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\

In point d)

using standard normal variate

x=20.17\\\\  z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17

8 0
3 years ago
What is an equation that can be written with 10x+5y=20 to form a pair of linear equations
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Y=2x+4 This is the equation
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