Ok! So, given a quadratic function<span>, </span>y<span> = ax</span>2<span> + bx + c, when "a" is positive, the </span>parabola <span>opens upward and the vertex is the minimum value. On the other hand, if "a" is negative, the graph opens downward and the vertex is the maximum value. Now, let's refer back to our original graph, </span>y<span> = </span><span>x2</span><span>, where "a" is 1.
Hope this helps.</span>
Answer:
x= -1, x=3
Step-by-step explanation:
The “zeros” of a quadratic function are where the parabola intersects the x axis. In that graph the parabola touches x=-1 and x=-3. Therefore that is the answer.
Answer:B. 1
Step-by-step explanation:
If it has more than 1 it won’t be a triangle anymore.
Answer: 3.5
Step-by-step explanation:
yes
Answer:
28
Length=2(x-1)
Width=5
Area=length*width = (2(x-1))(5) = (2x-2)(5) = 10x-10
29
His reasoning is illogical because whether or not an expression has a term that is being subtracted isn't relevant; technically there are an infinite amount of ways to represent a value. Plus you can just compute the expressions and see that they're equal:
6x-2x+4 = 4x+4
4(x-1) = 4x+4
30
The two expressions are equal because when you compute the expression 4(n+3)-(3+n) , you get 3n+9:
4(n+3)-(3+n) = 4n+12-3-n = 3n+9
31
The two expressions are equal because when you compute the expression 2(2n-1), you get 4n-2.
2(2n-1) = (2)(2n)+(2)(-1)=4n-2
32
5(g+14)=(5)(g)+(5)(14)=5g+70
The expressions aren't equal as 5(g+14) equates to 5g+70 and 5g+70≠5g+14.
