Evaluate ƒ(x ) = x 2 + 1 for ƒ(-1). Can someone explain how you figure this?
1 answer:
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Answer: Option B.
Step-by-step explanation:
For this exercise it is important to remember that, by definition, a relation is a function if and only if each input value has an unique output value.
The input values are the values of the variable "x" and the output values are the values of the variable "y".
You can observe in the table shown in the picture, that the input value -2 has two different output values:
Notice that the input vale -1 has two different output values too:
Therefore, based on this, you can conclude that the information given in the table is a relation but not a function.
