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3 years ago

Evaluate ƒ(x ) = x 2 + 1 for ƒ(-1). Can someone explain how you figure this?

Mathematics

1 answer:

Nastasia [14]3 years ago

8 0

if f(-1) substitute that into the equation.

f(-1) = (-1)2 +1

-1 = -1

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elena-s [515]

Answer:

Step-by-step explanation:

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Y_Kistochka [10]

Answer:

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4 years ago

Question 3 Unsaved

bazaltina [42]

Answer:

Step-by-step explanation:

DE given is

y''+8y'+15y=0, y(0)=0, y'(0)=1

Take Laplace on the DE

We get

$s^2 Y(s) -sY(0) -y'(0)+8(sY(s)-y(0))+15Y(s) =0\\s^2 Y(s) -s(0) -1+8(sY(s)-0)+15Y(s) =0\\Y(s)(s^2+8s+15)-1=0\\Y(s) = \frac{1}{s^2+8s+15}$

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Take inverse

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3 years ago