Ask question

Ask question

All categories

3 years ago

8

The sum of three consecutive numbers is greater than 40. The inequality that represents this is x+x+1+x+2>40. Which value of

x hold true for the inequality?

1 answer:

Umnica [9.8K]3 years ago

6 0

Answer:

x can be any integer greater than 12.

Step-by-step explanation:

x + x + 1 + x + 2 > 40

3x + 3 > 40

3x > 37

x > 12 1/3

x can be any integer greater than 12.

You might be interested in

Alguien lo puede resolver, pliss urgente

tangare [24]

Answer:

I can't understand the question sorry I don't speak spanish

Step-by-step explanation:

8 0

3 years ago

Find the value of b.

Nesterboy [21]

Answer: $230^{\circ$

Step-by-step explanation:

For convenience, I labeled some points as shown in the attached picture.

Also, I assume $\overline{AB}$ and $\overline{BC}$ are tangents to the circle.

$\overline{BO} \cong \overline{BO}$ (reflexive property)
$\overline{AB} \cong \overline{BC}$ (tangents drawn from a common external point are congruent)
$\angle BAO \cong \angle BCO$ (right angles are congruent)

Therefore, we know $\triangle ABO \cong \triangle CBO$ by HL.

Thus, by CPCTC,

$\angle AOB \cong \angle BOC \implies m\angle BOC=65^{\circ}\\\\\implies m\angle AOC=130^{\circ}$

This means the measure of minor arc AC is $130^{\circ}$ , and thus $b=360^{\circ}-130^{\circ}=\boxed{230^{\circ}}$

7 0

2 years ago

A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what

cluponka [151]

<u>Problem</u>

A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn?

<u>Work </u>

Probability = no. of favorable outcomes /total no. of outcomes

Probability of getting a blue marble=5/5+6+9=5/20

Probability of getting a red marble=6/20−1=6/19

5/20×6/19

<u>Answer</u>

3/20

So it is C.

4 0

3 years ago

Read 2 more answers

0.27=_ hundredths<br><br>please help me

Alexeev081 [22]

Answer:

27 hundredths

Step-by-step explanation:

.2 is in the tenths place,

.07 is in the hundredth place,

.27 is 27 hundredths

4 0

3 years ago

Read 2 more answers

Write 85% as it's fraction, as simply as possible

cricket20 [7]

Hey ! there

Answer:

Simplest fraction form of 85% is <u>1</u><u>7</u><u>/</u><u>2</u><u>0</u><u> </u><u>.</u>

Step-by-step explanation:

Question says that we have to write the <u>simplest</u><u> </u><u>form </u><u>of </u><u>8</u><u>5</u><u>%</u><u> </u><u>as </u><u>it's </u><u>fraction</u><u> </u><u>.</u>

<u>Solution </u><u>:</u><u> </u><u>-</u>

$\quad \longrightarrow \qquad \:85\%$

We know that ,

Percent ( % ) = <u>1</u><u>/</u><u>100</u>

So ,

$\quad \longrightarrow \qquad \: 85 \times \dfrac{1}{100} \:$

or ,

$\quad \longrightarrow \qquad \: \dfrac{85}{100}$

Reducing the fraction by cancelling it by 5 :

$\quad \longrightarrow \qquad \: \dfrac{ \cancel{85}}{ \cancel{100}}$

We get :

$\quad \longrightarrow \qquad \: \pink{\underline{\boxed{\frak{\dfrac{17}{20} }}}} \quad \bigstar$

Now , we can't reduce 17/20 .

<u>Henceforth</u><u> </u><u>,</u><u> </u><u>1</u><u>7</u><u>/</u><u>2</u><u>0</u><u> </u><u>is </u><u>the </u><u>simplest</u><u> </u><u>form </u><u>of </u><u>8</u><u>5</u><u>%</u><u> </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>

4 0

2 years ago

Read 2 more answers