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just olya [345]
4 years ago
14

What is an equation of a line in point slope form that passes through the points (7,-8) and (-4,6)?

Mathematics
1 answer:
maw [93]4 years ago
5 0

y=kx+b

for (7,-8): -8=7k+b. (function 1)

for (-4,6): 6=-4k+b (function 2)

Use function 2 - function 1

we get: 14=-11k

k=-14/11------>slope is -14/11

Now we know that first two options are wrong since they have the wrong slope for the function.

Plus -14/11 back to function 1/ or 2. Both are correct and can give you the answer. In this case I would plug it back to function 2.

6=14*4/11+b

b=66/11-56/11

b=10/11

We get y=-14/11x+10/11

subtract both side by 6.

y-6=-14/11x+10/11-66/11

y-6=-14/11x-56/11

y-6=-14/11(x+4)

So C is correct

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Describe the error Sarah made when simplifying the expression shown. -5(x-2)=-5x-10
prisoha [69]
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8 0
3 years ago
Find the expected value of the winnings
Orlov [11]

The expected value of the winnings from the game is $4

<h3>How to determine the expected value?</h3>

The payout probability distribution is given as:

Payout ($) 2 4 6 8 10

Probability 0.5 0.2 0.15 0.1 0.05

The expected value is then calculated as:

E(x) = \sum x * P(x)

This gives

E(x) = 2 * 0.5 + 4 * 0.2 + 6 * 0.15 + 8 * 0.1 + 10 * 0.05

Evaluate the expression

E(x) = 4

Hence, the expected value of the winnings from the game is $4

Read more about expected values at:

brainly.com/question/15858152

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7 0
2 years ago
I need help with this. Thanks <br><br><br> I need to find the degree
scoundrel [369]

Answer:

  119.05°

Step-by-step explanation:

In general, the angle is given by ...

  θ = arctan(y/x)

Here, that becomes ...

  θ = arctan(9/-5) ≈ 119.05°

_____

<em>Comment on using a calculator</em>

If you use the ATAN2( ) function of a graphing calculator or spreadsheet, it will give you the angle in the proper quadrant. If you use the arctangent function (tan⁻¹) of a typical scientific calculator, it will give you a 4th-quadrant angle when the ratio is negative. You must recognize that the desired 2nd-quadrant angle is 180° more than that.

__

It may help you to consider looking at the "reference angle." In this geometry, it is the angle between the vector v and the -x axis. The coordinates tell you the lengths of the sides of the triangle vector v forms with the -x axis and a vertical line from that axis to the tip of the vector. Then the trig ratio you're interested in is ...

  Tan = Opposite/Adjacent = |y|/|x|

This is the tangent of the reference angle, which will be ...

  θ = arctan(|y| / |x|) = arctan(9/5) ≈ 60.95°

You can see from your diagram that the angle CCW from the +x axis will be the supplement of this value, 180° -60.95° = 119.05°.

3 0
4 years ago
Find the vertex for each equation:
tamaranim1 [39]

1. (−3,−1)

2. (3,−5)

3. (−3,−4)

5 0
3 years ago
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