Given that the concentration has been modeled by the formula:
C(t)=50t/(t^2+25)
where:
t is time in hours.
The concentration after 5 hours will be given by:
t= 5 hours
plugging the value in the equation we get:
C(5)=(50(5))/(5^2+25)
simplifying the above we get:
C(5)=250/(50)=5 mg/dl
Answer: 5 mg/dl
Answer:
B
How many times greater in the area of the signal from transmitter
There is nothing there sorry
The value of n=12
The question might be wrong but according to your question this is the right answer
