Answer:
y=-1x^2 -4x +5
Step-by-step explanation:
Given points (-2, 9), (-4, 5), and (1, 0)
General quadratic equation is y=ax^2 +bx+c
plug in each point and frame three equations
(-2,9)
equation 1
(-4,5)
5 = 16a -4b+c equation 2
(1,0)
0= a + b + c equation 3
Use equation 1 and 3
multiply third equation by -1 and then add it with equation 1
4a - 2a + c = 9
-a -b -c = 0
---------------------
3a - 3b = 9
divide whole equation by 3
a - b = 3 equation 4
use equation 2 and 3
16a -4b+c = 5
-a -b -c =0
------------------------
15a -5b = 5
divide whole equation by 5
3a -b= 1 equation 5
use equation 4 and 5 . multiply equation 5 by -1
-3a +b =-1
a - b = 3
-----------------------
-2a = 2
a= -1
plug it in equation 4 and find out b
a - b = 3
-1 - b = 3
add 1 on both sides
-b = 4 so b= -4
Now plug in the values and find out c
a + b+c = 0
-1 -4 + c= 0
-5 +c =0
c=5
Now plug in the values in the general equation
y=ax^2 +bx+c
y=-1x^2 -4x +5
1. Number that adds up to -12 and multiplied by the same # that gives u -13. Set it up like this because both are negative so, u need 1 negative and 1 positive.
(x-13)(x+1)
2. Same rule applies. GCF
8y(4y+1)
3. (x+3)(x-3)
Answer:
I love algebra anyways
The ans is in the picture with the steps how i got it
(hope this helps can i plz have brainlist :D hehe)
Step-by-step explanation:
9514 1404 393
Answer:
∠B = 53°
∠C = 127°
∠D = 127°
Step-by-step explanation:
The trapezoid is isosceles, as indicated by the hash marks on sides AD and BC. This means it is symmetrical about the vertical center-line. Angles on the right will have the same measures as the symmetrical angles on the left.
So, you know immediately that ∠B = ∠A = 53°.
Because AB ║ DC, ∠A and ∠D are supplementary. That is, ...
∠D = ∠C = 180° -53°
∠D = ∠C = 127°
3 + 3 + 5 = 11 (11 total parts of the ratio.)
132 ÷ 11 = 12 (one part of the ratio)
Multiply 12 by the number of parts in the ratio:
12 × 3 = 36
12 × 3 = 36
12 × 5 = 60
Therefore, the final answer is 36:36:60 kg.
