Question

10. A cab company charges a flat rate of $2 plus an additional $0.50 for every mile traveled.

Answer 1

a.
f = total cab fare
m = distance travelled

f = 2 + 0.50m

b.
7.50 = 2 + 0.50m

c.
7.50 = 2 + 0.50m
7.50 - 2 = 0.50m
5.50 = 0.50m
5.50/0.50 = m
m = 11
 Sara travelled 11 miles.

d.
f = 2 + 0.50m
f = 2 + 0.50 x 10
f = 2 + 5
f = 7

When the cab fare is over $7.00 on the holidays, $1 is discounted off the fare.

e. 
Yes, Lupe traveled more than 10 miles. (refer to calculations used in c.)

Answer 2

Answer:

A cab company charges a flat rate of $2 plus an additional $0.50 for every mile traveled.

Part A:

Let the miles traveled be m

Total fare = $2+0.50m$

Part B:

When Sara arrived at your destination, her cab fare was $7.50.

Equation becomes:

$2+0.50m=7.50$

Part C:

Solving for m in part B.

$2+0.50m=7.50$

$=> 0.50m=7.50-2$

$=> 0.50m=5.50$

m = 11 miles

Part D:

The flat rate and the fee per mile are the same, but there is a $1 discount off the fare when the distance traveled is greater than 10 miles.

So, when m is greater than 10 miles then $1 is discount.

So, like when m = 11, The charges will be$7.50-1=6.50$

Part E:

Lupe’s cab fare on a holiday was $7.50. No he did not travel more than 10 miles. Because he would have paid $6.50 if he traveled more than 10 miles.