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Karo-lina-s [1.5K]

3 years ago

12

An isosceles triangle has at least two congruent sides. The perimeter of a certain isosceles triangle is at most 12 in. The leng

th of each of the two congruent sides is 5 in. What are the possible lengths of the remaining side?

1 answer:

Luba_88 [7]3 years ago

5 0

<span>5+5=10
12-10=2

Equal to or less than 2 inches...not sure
hope this helps</span>

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How many 2/4’s are in 2

swat32

Im pretty sure that answer is four!

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3 years ago

A matatu carries 14 passengers per trip. In

PilotLPTM [1.2K]

Answer:

"23,520"

Step-by-step explanation:

one trip: 14 passengers

one day: 3 trips

passengers: 80

80x14= 1,120

1,120x3= 3,360

3,360x7= 23,520

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3 years ago

What sine function represents an amplitude of 4, a period of pi over 2, no horizontal shift, and a vertical shift of −3?

mixer [17]

Answer:

$f(x) = 4sin(\frac{\pi}{2}x) - 3$ , the third one

Step-by-step explanation:

Explaining the sine function:

The sine function is defined by:

$S = Asin(p(x - x_{0})) + V$

In which A is the amplitude, $p = \frac{2\pi}{N}$ is the period, $x_{0}$ is the horizontal shift and V is the vertical shift.

So, in your problem:

The amplitude is 4, so A = 4.

The period is $\frac{\pi}{2}$ , so $p = \frac{\pi}{2}$ .

There is no horizontal shift, so $x_{0} = 0$ .

The vertical shift is −3, so V = -3.

The sine function that represents these following conditions is

$f(x) = 4sin(\frac{\pi}{2}x) - 3$ , the third one

4 0

3 years ago

A box contains 12 1/2 square feet of tiles and costs $40.21. What is the price per square feet?

liraira [26]

The answer is $3.21.
To find the answer, divide the total cost by the number of sq ft to get the price per sq ft.

3 0

4 years ago

Read 2 more answers

Consider the following planes. x + y + z = 6, x + 7y + 7z = 6 (a) Find parametric equations for the line of intersection of the

Lelechka [254]

Answer:

a. $x=6,y=-6t,z=6t$

b. $\theta=29.5^{\circ}$

Step-by-step explanation:

We are given that

$x+y+z=6$

$x+7y+7z=6$

a.Substitute z=0

$x+y=6$ ...(1)

$x+7y=6$ ..(2)

Subtract equation (1) from equation (2)

$6y=0$

$y=0$

Substitute y=0 in equation(1)

$x=6$

The point (6,0,0) lie on a line.

$r_0=(x_0,y_0,z_0)=(6,0,0)$

Let $A=$

$B=$

$A\times B=\begin{vmatrix}i&j&k\\1&1&1\\1&7&7\end{vmatrix}$

$A\times B=i(7-7)-j(7-1)+k(7-1)=-6j+6k$

Therefore, the vector $a'=(a,b,c)=$

Line is parallel to vector a' and passing through the point (6,0,0).

The parametric equation is given by

$x=x_0+at,y=y_0+bt,z=z_0+ct$

Using the formula

The parametric equation is given by

$x=6,y=-6t,z=6t$

Angle between two plane

$a_1x+b_1y+c_1z=d_1$

and $a_2x+b_2y+c_2z=d_2$

$cos\theta=\frac{(a_1,b_1,c_1)\cdot (a_2,b_2,c_2)}{\sqrt{a^2_1+b^2_1+c^2_1}\cdot \sqrt{a^2_2+b^2_2+c^2_2}}$

Using the formula

$cos\theta=\frac{(1,1,1)\cdot(1,7,7)}{\sqrt{1+1+1}\times \sqrt{1+7^2+7^2}}$

$cos\theta=\frac{1+7+7}{\sqrt 3\times 3\sqrt{11}}$

$cos\theta=\frac{15}{3\sqrt{33}}}=\frac{5}{\sqrt{33}}$

$\theta=cos^{-1}(0.87)=29.5^{\circ}$

Where $\theta$ in degree.

3 0

3 years ago