To add monomials, you have to look at the variables that are accompanied by their coefficients. In the given problem, (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd), you can combine both cd ut nt cd and c² and cd and d and d and c² because they have different variables.
<span>(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)
(-4c</span>² + 8c²) + (7cd + 4cd) + (8d - 3d)
4c² + 11cd + 5d
Answer:
1 ≤ x < 7
Step-by-step explanation:
−2+3≤x−3+3<4+3 (Add 3 to all parts)
Given:
The function is:
To find:
The inverse of the given function, then draw the graphs of function and its inverse.
Solution:
We have,
Step 1: Substitute 
.
Step 2: Interchange x and y.
Step 3: Isolate variable y.
Step 4: Substitute 
.
Hence, the inverse of the given function is and the graphs of these functions are shown below.
Well, what are the pictures??
C.) 30 since they both have 5's just take them out then subtract 50 and 20 *but make sure u take out the decimal though* so after u subtract u will get 30 then line it up and put the decimal back then it will be .30
