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Afina-wow [57]
3 years ago
5

If f(x) = 3x^2 +1 and g(x) = 1-x, what is the value of (f-g)(2)

Mathematics
1 answer:
aleksley [76]3 years ago
8 0

Answer:

14

Step-by-step explanation:

Let's find (f-g)(x)

3x^{2} + 1 - (1-x)\\3x^{2} + 1 -1 + x\\3x^{2} + x

Now let's plug in x=2, so to find (f-g)(2)

3(2)^{2} + 2\\12 + 2 = 14

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(From workbook MATH 8A)​
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8 bc 2/3 x 18= 12 and 12-4 = 8 :) sorry if im wrong tho
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THIS QUESTION IS WORTH 15 POINTS
ikadub [295]

Answer:

3.7

This means that the answer is past the 3 point on the number line and 3 tick marks before the 4 point.

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3 years ago
Rolling 7 or 11 on the first roll is a win probability of winning on 1st roll
gtnhenbr [62]

1/6 plus 1/18, which equals to 2/9. Suppose we roll 4 on the first roll (the probability of rolling 4 is 1/12). On each successive roll the probability of rolling 7 is 1/6 and the probability of rolling 4 is 1/12.

[i.dk how this can help but if you got a 7 or 11 rolling on the first round you would probably win]

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3 years ago
I'm having trouble with this problem what is 2+2
V125BC [204]

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4

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7 0
2 years ago
New codes to destroy the First Order are known to exist. With probability 0.6, the codes are hidden by Leia; with probability 0.
elixir [45]

Answer: (a). 0.62 (b). 0.53

Step-by-step explanation:

Let us start by defining some events seen:

Given;

L rep the event that codes hidden Leia

BB represents the codes hidden in BB-8

H is the event that codes hidden by Hah

C-3PO rep the codes hidden in C3PO

Giving the probabilities, we have that

P(L)  =  probability that codes are hidden by Leia = 0.6

P(H) = probability that codes are hidden by Hah = 0.4

where P(BB/L) = 70/10 i.e 70%

P(C-3PO/L) = 1 - P(BB/L) = 1 - 7/10 = 3/10

Also, P(BB/H)  = 1/2 = P(C-3PO/H)

We can say that Han Solo is likely to hide them in aceta BB-8 and C-3PO

To begin,

(a). The question tell us to find the probability that the codes are with BB-8.

First of all, we find P(BB).

P(BB) = P(L)*P(BB/L) + P(H)*P(BB/H)

solving this we get

P(BB) = 0.6*7/10 + 0.4*1/2 = 0.62

Therefore,  the probability that the codes are with BB-8 = 0.62

(b). The second question says;

Given that the codes are with C-3PO, what is the probability the codes were hidden by Han Solo?

This tell us to find P(H/C-3PO)

P(H/C-3PO) = P(C-3PO/H)*P(H) / P(C-3PO/H) + P(C-3PO/L)*P(L)

inputting the values gives us;

P(H/C-3PO) = 1/2 * 0.4 / ( 1/2 *0.4 + 3/10 *0.6) = 0.53

SO we have that the probability the codes were hidden by Han Solo = 0.53

cheers I hope this was helpful!!

3 0
3 years ago
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