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myrzilka [38]
3 years ago
7

Write the equation of the line containing the point (4, 6) and having a slope of 4 in slope-intercept form.

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
8 0
6 = 4(4) + c
c = - 10
y = 4x - 10
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Choose the equation of the line that is parallel to the y-axis.
kodGreya [7K]

Answer:

x=-2

Step-by-step explanation:

If x always = -2, it is a straight vertical line which means it is parallel to the y axis

4 0
3 years ago
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ustin wants to use 188 ft of fencing to fence off the greatest possible rectangular area for a garden. What dimensions should he
Tema [17]

Answer:

I would say that it should be 48 ft long and 46 ft wide, the area would be 2208 square feet

Step-by-step explanation:

I will try my best to answer this.

I would start by dividing 188 by 4

this gives you a 47*47 square

if it needs to be a rectangle I would then make the sides 48, 48, 46, and 46

48*46 would be the dimensions

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5 0
3 years ago
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Arturiano [62]

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60? I'm really not sure mate, i'm really sorry if it's wrong.

Step-by-step explanation:

7 0
2 years ago
4/9x+1/5x=58<br> plzhelp
Olenka [21]

Answer:

Solution

x = 90

Step-by-step explanation:

Combine multiplied terms into a single fraction

4

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+

1

5

⋅

=

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8

\frac{4}{9}x+\frac{1}{5} \cdot x=58

94​x+51​⋅x=58

4

9

+

1

5

⋅

=

5

8

\frac{4x}{9}+\frac{1}{5} \cdot x=58

94x​+51​⋅x=58

2

Combine multiplied terms into a single fraction

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6 0
3 years ago
What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?
xxMikexx [17]

We have been given an equation of hyperbola \frac{(y+3)^2}{81}-\frac{(x-6)^2}{89}=1. We are asked to find the center of hyperbola.  

We know that standard equation of a vertical hyperbola is in form \frac{(y-k)^2}{b^2}-\frac{(x-h)^2}{a^2}=1, where point (h,k) represents center of hyperbola.

Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.

To find the value of k, we need to rewrite our equation as:

\frac{(y-(-3))^2}{81}-\frac{(x-6)^2}{89}=1

Now we can see that value of k is -3. Therefore, the vertex of given hyperbola will be at point (6,-3) and option D is the correct choice.

6 0
3 years ago
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