U.V this is the easy step by step equals 9.01. U The graph has to be lined
Let x and y be the dimension of the rectangle. Suppose x is the width and y is the length. Since the perimeter is 36, we have
![2(x+y)=36 \iff x+y=18 \iff y = 18-x](https://tex.z-dn.net/?f=%202%28x%2By%29%3D36%20%5Ciff%20x%2By%3D18%20%5Ciff%20y%20%3D%2018-x%20)
If we increase the length by 1, we change
. Similarly, if the width is increased by 2, we change
. So, the increased area is
![(x+2)(y+1)=30](https://tex.z-dn.net/?f=%20%28x%2B2%29%28y%2B1%29%3D30%20)
If we substitute the value for y deduced in the first equation, we have
![(x+2)(18-x+1)=30 \iff (x+2)(19-x) = 30 \iff -x^2+17x+38 = 30 \iff x^2-17x-8=0](https://tex.z-dn.net/?f=%20%28x%2B2%29%2818-x%2B1%29%3D30%20%5Ciff%20%28x%2B2%29%2819-x%29%20%3D%2030%20%5Ciff%20-x%5E2%2B17x%2B38%20%3D%2030%20%5Ciff%20x%5E2-17x-8%3D0)
The solutions to this equation are
![\dfrac{17\pm\sqrt{321}}{2}](https://tex.z-dn.net/?f=%20%5Cdfrac%7B17%5Cpm%5Csqrt%7B321%7D%7D%7B2%7D%20)
One of them is negative, so we have to choose the positive one:
![x=\dfrac{17+\sqrt{321}}{2}](https://tex.z-dn.net/?f=%20x%3D%5Cdfrac%7B17%2B%5Csqrt%7B321%7D%7D%7B2%7D%20)
Which implies
![y = 18 - \dfrac{17+\sqrt{321}}{2} = \dfrac{19-\sqrt{321}}{2}](https://tex.z-dn.net/?f=%20y%20%3D%2018%20-%20%5Cdfrac%7B17%2B%5Csqrt%7B321%7D%7D%7B2%7D%20%3D%20%5Cdfrac%7B19-%5Csqrt%7B321%7D%7D%7B2%7D%20)
True because it is hope it helps
Given simplification:
3√7 + 7√63 + (√7/7)
= 3√7 + 7√(9*7) + (√7/7)
= 3√7 + 7*3√7 + (√7/7)
= 3√7 + 21√7 + (√7/7)
= (3+21)√7 + (√7/7)
= 24√7 + (√7/√7)
= (7*24√7 + √7)/7
= (168√7 + √7)/7
= (169√7)/7
<u>Answer</u><u>:</u><u>-</u> 3√7 + 7√63 + (√7/7) = (169√7)/7.
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To find the product 3/7 times 4/9, Cameron simplified 3/7 to 1/7 and the multiplied the fraction 1/7 and 4/9 to find the product 4/63....
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Answer:
D would be the best answer. Because 2 x 8 = 16
Step-by-step explanation: