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3 years ago

16

Mathematics

2 answers:

enot [183]3 years ago

5 0

Answer:

D) 4.01 miles

Step-by-step explanation:

2.87 miles from Monday + 1.14 miles =4.01 ran on Tuesday

lutik1710 [3]3 years ago

4 0

The answer is is D) 4.01

if she ran 1.14 miles further than she did on monday than you would add the miles from monday to the amount of mile further she walked tuesday.

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Let U={q, r, s, t, u, V, W, X, Y, Z},

trapecia [35]

Answer:

Ooh is theis unions I did it but

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2 years ago

Find the slope of the line passing through the two points.<br><br> (2.1, 3.8), (3.1, 7.6)

bixtya [17]

Answer:

3.8

Step-by-step explanation:

Slope formula- m = y2 - y1

x2 - x1

x1, y1

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2 years ago

A rectangle is shown with length x plus 10 and width 2 x plus 5. The inside of the rectangle is shaded other than an unshaded sq

klio [65]

Answer:

Step-by-step explanation:

A rectangle is shown with length x plus 10 and width 2 x plus 5.

so the rectangle area = length * width

= (x + 10) * (2x + 5)

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so the unshaded square area = (x + 1) * (x + 1)

the shaded area = rectangle area - square area

= (x + 10) * (2x + 5) - (x + 1) * (x + 1)

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3 years ago

Read 2 more answers

What are greater than and less than symbols?

schepotkina [342]

> is greater than
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3 years ago

Our faucet is broken, and a plumber has been called. The arrival time of the plumber is uniformly distributed between 1pm and 7p

Ymorist [56]

Answer:

$E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours$

$Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2$

Step-by-step explanation:

Let A the random variable that represent "The arrival time of the plumber ". And we know that the distribution of A is given by:

$A\sim Uniform(1 ,7)$

And let B the random variable that represent "The time required to fix the broken faucet". And we know the distribution of B, given by:

$B\sim Exp(\lambda=\frac{1}{30 min})$

Supposing that the two times are independent, find the expected value and the variance of the time at which the plumber completes the project.

So we are interested on the expected value of A+B, like this

$E(A +B)$

Since the two random variables are assumed independent, then we have this

$E(A+B) = E(A)+E(B)$

So we can find the individual expected values for each distribution and then we can add it.

For ths uniform distribution the expected value is given by $E(X) =\frac{a+b}{2}$ where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got: