Answer:
5
Step-by-step explanation:
Answer:
the answer is 24
Step-by-step explanation:
i got that answer in edgenuity
<span>The amount P as a function of t (in years) is given by
P(t) = P0 (1 + r/n)^(t n)
So if n = 4, and r = 0.02, and P0 = 1000, then
P(t) = 1000 (1 + 0.02/4)^(4 t) = 1000 (1 + 0.005)^(4 t)
At the end of the first quarter, t = 1/4, so
P(1/4) = $1000 (1.005)^(1) = $1005
At the end of the second quarter, t = 1/2 , therefore
P(1/2) = $1000 (1.005)^(2) = $1000 (1.010025) = $1010.03
At the end of the third quarter , t = 3/4, therefore
P(3/4) = $1000 (1.005)^(3) = $1000 (1.015075125) = $1015.08
At the end of the year, t = 4, therefore
P(1) = $1000 (1.005)^4 = $1000 (1.020150500625) = $1020.15
As for the second question, after the first period (quarter),
the formula becomes
P = P0 (1.005)^1 = 1.005 P0
which is choice A. </span>
In this problem, you are asked to compute for the volume of
the spherical paintball. The formula in computing the volume of the sphere is:
V = 4/3 (pi) r^2
Where r = the radius of the sphere
Since the given measurement is in diameter, you need to
compute the radius of the sphere. The radius of the sphere is half its
diameter. Therefore, the radius of the sphere is 0.75 cm (1.5 cm / 2).
Substituting the radius to the formula and using 3.14 as the
value of pi:
V = 4/3(3.14)(0.75)^2
V = 2.355 cm^3 or 2.36 cubic centimeters (note that cubic
centimeter is equal to mL)
Therefore, there are approximately 2.36 mL of paint in the paintball.
Answer:
to be honest I dont know
Step-by-step explanation:
I dont know how.
