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yan [13]
3 years ago
15

Find the domain and range of the function: f(t)=sec[((pi)t)/4]

Mathematics
1 answer:
beks73 [17]3 years ago
3 0

The domain and range of the function f(t)=sec[((pi)t)/4] are the following:

<span>Domain: All the real numbers except t = 2 + 4k, where k is an integer. </span>

Range: (-∞, -1] U [1, ∞)

I am hoping that these answers have satisfied your queries and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

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A hotel offers a reward program based on the number of night stayed. The function f(x) represents the number of free nights earn
iris [78.8K]

Answer:

a. A customer earns 1 free night per 10 nights stayed.  

Step-by-step explanation:

The missing function is:

f(x) = x/10  

The missing options are:

<em> a. A customer earns 1 free night per 10 nights stayed.  </em>

<em> b. A customer starts with 1 free night and then earns another free night after every 10 nights stayed. </em>

<em> c.A customer earns x – 10 free nights for every 10 nights stayed.  </em>

<em> d. A customer earns 10 free nights after x number of nights stayed. </em>

The function means that after a customer stayed 10 nights, a free night is earned. That is, replacing x = 10 into the function, we get:

f(10) = 10/10  = 1

which means 10 nights are equivalent to 1 free night.

7 0
3 years ago
log 95 The expression Tog2 is the result of applying the change of base formula to a logarithmic expression. Which could be the
Ivanshal [37]

Answer:

third option: log_2  1/3

Step-by-step explanation:

change of base formula:

log_b  a= (log_x a)/(log_x b)

(log 1/3)/(log 2)

apply reverse change of base formula

2 from log 2 becomes new base, and 1/3 becomes the other number

=log_2  1/3

7 0
2 years ago
Which equation represents a linear function? Equation 1: y^3 = 2x +1 Equation 2: y= 3x +1 Equation 3: y= 5x^2 - 1 Equation 4: y=
Yuri [45]
the second equation is linear
8 0
3 years ago
Please solve and explain how. Photo attached
geniusboy [140]

Answer:

Step-by-step explanation:

\frac{2}{k^2-2k}=1-\frac{1}{k^2-2k}

multiply by \frac{k^2-2k}{1} on each side

2=k^2-2k-1

add 1 on both sides 3=k^2-2k

make it equal 0

0=k^2-2k-3

Factor

(k-3)(k+1)

answer is 3 and -1

7 0
3 years ago
Write the following inequality in slope-intercept form. −6x + 2y ≤ 42
zubka84 [21]
Add the 6x to both sides. Then divide both sides by 2 to get y by itself.

y <= 6x + 42

Note: if it were a -2y, you’d have to flip the inequality sign when dividing by that negative 2.

:)
7 0
3 years ago
Read 2 more answers
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