3 years ago

Find the domain and range of the function: f(t)=sec[((pi)t)/4]

Mathematics

1 answer:

beks73 [17]3 years ago

3 0

The domain and range of the function f(t)=sec[((pi)t)/4] are the following:

<span>Domain: All the real numbers except t = 2 + 4k, where k is an integer. </span>

Range: (-∞, -1] U [1, ∞)

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(Picture) MULTIPLYING MONOMIALS AND BINOMIALS

motikmotik

Answer:

Second option: 81y^4 - 16x^2, the difference of squares

Step-by-step explanation:

(9y^2-4x)(9y^2+4x) is a special product named difference of squares, then we can apply this formula:

(a-b)(a+b)=a^2-b^2, with a=9y^2 and b=4x, then:

(9y^2-4x)(9y^2+4x)=(9y^2)^2 - (4x)^2

(9y^2-4x)(9y^2+4x)=(9)^2 (y^2)^2 - (4)^2 (x)^2

(9y^2-4x)(9y^2+4x)=81y^(2*2) - 16x^2

(9y^2-4x)(9y^2+4x)=81y^4 - 16x^2

7 0

3 years ago

What is the value of 3x 2 squared + 5x when x=3

Serhud [2]

3•2=6. When you square 6, you get 36. Add 5x to that. 5x=15. 36+15=51

Cassie read 155 pages one day, and we need to find the unknown value of “x”. All you have to do is add 155+x=325.