Since there is no repetition allowed, there are 10 possibilities for the 1st digit, 9 for the 2nd, 8 for the 3rd, and 7 for the 4th. This gives a total of (10)(9)(8)(7) = 5040 four-digit codes.
For all odd digits to be used, there are 5 possibilities for the 1st digit (1,3,5,7,9), 4 for the 2nd, 3 for the 3rd, 2 for the 4th. This gives a total of (5)(4)(3)(2) = 120 codes that only use odd digits.
Therefore there are 5040 - 120 = 4920 codes that do not consist of all odd digits. The probability is 4920/5040 = 41/42.
Answer:
[tex] \frac{354 \times 6789}{98 \times - 4} = - −6,130.8827
Okay, so you didn't really put anything for me to know what you wanted to solve, so I'm going to assume this is Scientific Notation:
We have:
10^5 = 100,000 x 4.84 would be: 484,000
10^2 = 100 x 3.9 would be: 390
10^7 = 10,000,000 x 8.91 would be: 89,100,000
Answer:
180 pages
Step-by-step explanation:
Since her photocopy session is 25 pages per minute, the total number of pages photocopied in 4 hour session can be calculated as;
number of pages = time × speed
= (4 × 60) × 25
= 240 ×25
= 6000 pages
Thus, number of pages photocopied in 4 hours is 6000.
For every 100 pages, 3 would contain some type of printing error. The number of pages she expect with printing error during 4 hour session can be determined as;
=
× 3
= 60 × 3
= 180 pages
The expected number of pages with printing error during 4 hour photocopying session is 180 pages.
Answer:
Han= 24 minutes
His sister= 24 minutes
His Dad= 36 minutes
Grandmother= 42 minutes
Step-by-step explanation:
Please see attached picture for full solution.
Where the working split, see the right hand side.
The question states that Han's Dad sits 1.5 times as long as both Han and his sister. There could be 2 interpretations for this:
- Dad sits for 1.5 times of (Han and his sister)
- Dad sits for 1.5 times of Han and 1.5 times of Han's sister
I've done the working for both scenarios and found out that the 1st case cannot be true since Dad would've sat for 50.4 minutes when the bus ride is only 42 minutes! Moreover, there wouldn't be enough information to know how long Han and his sister sat for.
The second case is possible and it's working is on the right.
Feel free to ask if you have any enquiries :)