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3 years ago

WILL GIVE BRAINELIST WHOEVER ANSWER FIRST

Mathematics

2 answers:

Nataliya [291]3 years ago

8 0

Answer:

It is 5, I just did the test on Ed

Leokris [45]3 years ago

4 0

Answer:

Step-by-step explanation:

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The length of a pencil is 128 mm correct to the nearest

Cloud [144]

128 mm is the corrrect but not corre I by score u should.

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3 years ago

1. Juan bought a pair of shoes costing P923.00 and a tie costing P275.00. He gave the seller P2, 000.00. How much change did he

EleoNora [17]

$2000.00-923.00-275.00=802.00$

4 0

3 years ago

Tan x + sqrt(3) = - 2 tan x

Svet_ta [14]

9514 1404 393

Answer:

nπ -π/6 . . . for any integer n

Step-by-step explanation:

tan(x) +√3 = -2tan(x) . . . . . given

3tan(x) = -√3 . . . . . . . . . . . add 2tan(x)-√3

tan(x) = -√3/3 . . . . . . . . . . divide by 3

x = arctan(-√3/3) = -π/6 . . . . use the inverse tangent function to find x

This is the value in the range (-π/2, π/2). The tangent function repeats with period π, so the set of values of x that will satisfy this equation is ...

x = n·π -π/6 . . . . for any integer n

8 0

3 years ago

What degree of rotation is represented on this matrix

Korvikt [17]

Answer:

Option B is correct

the degree of rotation is, $-90^{\circ}$

Step-by-step explanation:

A rotation matrix is a matrix that is used to perform a rotation in Euclidean space.

To find the degree of rotation using a standard rotation matrix i.e,

$R = \begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$

Given the matrix: $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

Now, equate the given matrix with standard matrix we have;

$\begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$ = $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

On comparing we get;

$\cos \theta = 0$ and $-\sin \theta =1$

As,we know:

$\cos \theta = \cos(-\theta)$

$\sin(-\theta) = -\sin \theta$

$\cos \theta = \cos(90^{\circ}) = \cos( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

and

$\sin \theta =- \sin (90^{\circ}) = \sin ( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

Therefore, the degree of rotation is, $-90^{\circ}$

7 0

3 years ago

Evaluate this expression <br> mn^2 <br> (btw m=2 and n=3)

Molodets [167]

Answer:

529

Step-by-step explanation:

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3 years ago