Question

Write the expression(4x-2)·6(2x+7) in the standard form of a quadratic expression, ax²+bx+c

Answer 1

$(4x-2)*6(2x+7)=(4x-2)*(12x+42)$ I can do this because of distribution, which I will use again in the following: $(4x-2)*(12x+42)=48x^2-24x+168x-84=48x^2+144-84$

This is the answer.

Answer 2

(4x - 2)(6(2x + 7)) = 0
(4x - 2)(6(2x) + 6(7)) = 0
(4x - 2)(12x + 42) = 0
48x² + 168x - 24x - 84 = 0
48x² + 144x - 84 = 0
x = -144 +/- √(144² - 4(48)(-84))
                        2(48)
x = -144 +/- √(20,736 - 16,128)
                           96
x = -144 +/- √(4,608)
                  96
x = -144 +/- 67.88
                96
x = -1.5 +/- 0.707083
x = -1.5 + 0.707083      x = -1.5 - 0.707083
x = -0.792917               x = -2.207083