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3 years ago

PLEASE HURRY!!!!!!!!

Mathematics

1 answer:

IceJOKER [234]3 years ago

6 0

Answer:

y= -3/7x + 3

Step-by-step explanation:

When you sub in 0 for x, the result is 3 for y, When you sub in 7 for x, the result is 0 for y. This is the only equation that satisfies it.

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Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck

Nimfa-mama [501]

$\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}$
$\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}$

Now, isolate the variables, so you can integrate.
$(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}$
$\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}$
$2y - \frac{y^{2}}{2} = sin^{-1}\frac{x}{\sqrt{2}} + \frac{1}{2}C$

$4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C$
$y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} = 4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C$

$y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$
$y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$

At x = 1, y = 0.
$0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$
$-2 = \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C > 0$
$\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C$
$0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C$
$C = -2sin^{-1}\frac{1}{\sqrt{2}} = -2\frac{\pi}{4}$
$C = -\frac{\pi}{2}$

$\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}$

6 0

3 years ago

42 points giv away PLZ ANSWER RN (5/8+3/4) divided by (-2/3 - 5/6)

Triss [41]

Answer:

when you divide you get -11/12

if you have a calculator you could add the 5/8 and 3/4

then add the -2/3 and the -5/6

then divide the first answer by the second answer

8 0

3 years ago

Read 2 more answers

Use properties to find the sum or product 93+(68+7)

Vlad [161]

Answer:

Step-by-step explanation:

93+(75)

= 168

3 0

3 years ago

Student A has a probability of 0.9 of solving a problem while student B has a probability of 0.6 of solving the problem. What is

Vilka [71]

answer

0.54

explanation

since student A and student B are independent of each other, we multiply their individual probabilities to get the probability of both solving the problem

A * B

= 0.9 * 0.6

= 0.54

there is a 0.54 probability that both will solve the problem

6 0

3 years ago

How do i add 567,890 567,096

marissa [1.9K]

567,890
+567,096
________
1,134,986

3 0

3 years ago