Answer:
x and (x - 6)
Step-by-step explanation:
y = a(x - h)² + k
h = 3 k = -2
y = a (x - 3)² -2
For point (0 , 0) on the function
0 = a (0 - 3)² -2
0 = 9a - 2
a = 2/9
a (x - 3)² -2 = 2/9 (x² - 6x + 9) - 2 = 2/9 * x * (x - 6) + 2 - 2 = 2/9 * x * (x-6)
1.6 I think I’m sorry if it’s incorrect
For this case we have the following equation:

Where,
t: time
v: initial speed
s: initial height
Substituting values we have:

By the time the ball hits the ground we have:

From here, we clear the value of time:
Using the quadratic equation we have:

Doing the calculations we have:

Discarding the negative root, we have that the time is:
Answer:
it takes the ball to hit the floor about:
1.15 seconds
Answer:
y = x^2 +8x +16
Step-by-step explanation:
t can be written in terms of x, then substituted into the equation for y.
x = t -4
x + 4 = t
y = t^2 = (x +4)^2
y = x^2 +8x +16