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AlexFokin [52]
3 years ago
8

Use Random number generator and simulate 1000 long columns, for each of the three cases. Example: for the Car type 1, use Number

of variables=1, Number of random numbers=1000, Distribution=Normal, Mean=520 and Standard deviation=110, and leave random Seed empty. Next: use either sorting to construct the appropriate histogram or rule of thumb to answer the questions: 13. What is approximate probability that Car Type 3 has annual cost less than $550?

Mathematics
1 answer:
sertanlavr [38]3 years ago
7 0

Answer:

Step-by-step explanation:

The question is incomplete since they do not give information about the Car type 3.

We will do it in a generic way, we will say that the Car type 3 has a mean of M and a standard deviation SD.

We would be:

P (CT3 <550) = P [z <(550 - X) / SD]

Now if we give it values, for example that X = 600 and SD = 120

It would remain:

P (CT3 <550) = P [z <(550 - 600) / 120]

P (CT3 <550) = P [z <-0.42]

We look for this value in the normal distribution table (attached) and it shows us that the probability is approximately 0.3372, that is, 33.72%

What you need to do is replace the X and SD values of theCar type 3 in the equation above how I just did and you will get the result.

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balandron [24]
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3 years ago
Kelsey is putting on sunscreen. She uses 3 ml to cover 45cm to the power of 2 of her skin. She want to know how many milliliters
Artemon [7]

Answer: She would require 16 ml cover 240cm^2 of her skin

Step-by-step explanation:

Let m represent the milliliters of sunscreen required to cover her skin.

Let a represent the area of her skin that was covered. She assumes the the relationship between milliliters of sunscreen and the area is proportional. Introducing the constant of variation, k, the expression becomes

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4 0
3 years ago
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miss Akunina [59]
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bearhunter [10]

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alexgriva [62]

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3 years ago
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