Question

t{x - 3 } + 2" align="absmiddle" class="latex-formula">
find domain and range

Answer 1

Since Domain are all the inputs possible, and square root cannot do negative numbers, x can't go below 3, otherwise the thing will be a complex number. So, your domain is:
$x \geq 3$

Then, your range has to be greater than 0 because a principal square root symbol, if passed a positive number will return a positive answer. So, your range should be:
$x \geq 0$

But, then you add 2 to it, so it then turns into:
$x \geq 2$