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lubasha [3.4K]
3 years ago
11

The rule is “1, 2.” What is the 42nd number?

Mathematics
2 answers:
ivolga24 [154]3 years ago
5 0

Answer:

42

Step-by-step explanation:

tiny-mole [99]3 years ago
3 0
42, because it is just going up by ones
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420 miles because it’s just correct
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Helpppp pleaseee ! i don’t understand
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40

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Round 523,837 to the nearest thousand
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Answer:

524,000

Step-by-step explanation:

First, we mark the two nearest thousands.

They are 523,000 and 524,000.

The midpoint is 523,500.

Ignoring the thousands, ten-thousands, and hundred-thousands place, we have 837.

Now, is 837 closer to 0 or 1000?

It's closer to 1000, so 524,000 is our answer.

ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘᴇᴅ!

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Find the equation of a line which is parallel to y= 2/5 x + 17 and passes through (-15,12)
Naddika [18.5K]

Answer:

y = 2/5x + 18.

Step-by-step explanation:

The line will have the same slope of 2/5.

Using the point-slope form of a line:

y - 12 = 2/5(x - -15)

y - 12 = 2/5(x + 15)

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Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
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Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

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