The numerator is 5 so it’s on the left and and denominator 8 is on the right so it 5:8 is the answer
Answer:
Option C. x^2-18x-81
Step-by-step explanation:
A. 16a^2-72a+81
x^2-2xy+y^2=(x-y)^2
x^2=16a^2→sqrt(x^2)=sqrt(16a^2)→x=sqrt(16) sqrt(a^2)→x=4a
y^2=81→sqrt(y^2)=sqrt(81)→y=9
2xy=2(4a)(9)→2xy=72a equal to the second term of the expression, then we can factor as a perfect square trinomial:
16a^2-72a+81=(4a-9)^2
B. 169x^2+26xy+y^2
a^2+2ab+b^2=(a+b)^2
a^2=169x^2→sqrt(a^2)=sqrt(169x^2)→a=sqrt(169) sqrt(x^2)→a=13x
b^2=y^2→sqrt(b^2)=sqrt(y^2)→b=y
2ab=2(13x)(y)→2ab=26xy equal to the second term of the expression, then we can factor as a perfect square trinomial:
169x^2+26xy+y^2=(13x+y)^2
C. x^2-18x-81
a^2+2ab+b^2=(a+b)^2
This expression does not factor as a perfect square trinomial because the third term is negative (-81).
D. 4x^2+4x+1
a^2+2ab+b^2=(a+b)^2
a^2=4x^2→sqrt(a^2)=sqrt(4x^2)→a=sqrt(4) sqrt(x^2)→a=2x
b^2=1→sqrt(b^2)=sqrt(1)→b=1
2ab=2(2x)(1)→2ab=4x equal to the second term of the expression, then we can factor as a perfect square trinomial:
4x^2+4x+1=(2x+1)^2
The diagonals bisect each other at their midpoints.
Find the midpoint of diagonal WY :-
= (-1+6/,2 , (7-2)/2
= (2.5, 2.5) answer
Its C
the number before times itself
22 because 2x2=4+6=10+6=16 3x2=6 witch means u add 16+6 and that is 22
