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AfilCa [17]
3 years ago
12

The product of x and 7

Mathematics
2 answers:
EastWind [94]3 years ago
8 0
Write that as 7x.  Writing it as x7 could lead to confusion.  7*x would be OK.

Kipish [7]3 years ago
8 0

Answer:

7x

Step-by-step explanation:

The PRODUCT is multiplication therefore, 7 is multiplying by x.

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A car traveled at a constant speed for 4 hours and covered 144.6 miles. It used 12 gallons of gas to travel this distance. How f
FromTheMoon [43]
In one hour he traced the distance of: 36.15 miles

With one gallon of gas he went: 12.05 miles 

;) There you go! Good Luck!
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3 years ago
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What is the least common multiple of 2,6 and 15?
Alex

Answer:

LCM of 6 and 15 by Listing Multiples

Step 2: The common multiples from the multiples of 6 and 15 are 30, 60, . . . Step 3: The smallest common multiple of 6 and 15 is 30.

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3 years ago
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A show uses 12 gallons of water in three minutes complete the table and the graph.
gregori [183]

Answer:

2 mins= 8 gallons 3 mins= 12 gallons 4 mins= 16 gallons 5 mins= 20 gallons 6 mins= 24 gallons

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5 0
3 years ago
HELP PLS ASAP!!!! PLS
Reptile [31]

Answer:

x=3

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Directions:Simplify the following monomials.SHOW ALL STEPS!
Mandarinka [93]

Answer:

<u>7. Ans</u>;

\frac{6 {a}^{5}  {b}^{7} }{ - 2 {a}^{3} {b}^{7}  }   =  \frac{2 {a}^{3} {b}^{7}(3 {a}^{2} )  }{ - 2 {a}^{3}  {b}^{7} }  =  - 3 {a}^{2}

___o____o___

<u>8. Ans</u>;

\frac{ - 20 {x}^{3}  {y}^{2} }{ - 5 {x}^{3}y }  =  \frac{ - 5 {x}^{3}y(4y) }{ - 5 {x}^{3}y }  = 4y

___o___o___

<u>9. Ans</u>;

\frac{ - 16 a {b}^{4}  }{4 {b}^{3} }  =  \frac{4 {b}^{3}( - 4ab) }{4 {b}^{3} }  =  - 4ab

____o____o____

<u>10. Ans;</u>

\frac{21 {m}^{8}  {n}^{5} }{27 {m}^{5} {n}^{4}  }  =  \frac{3 {m}^{5} {n}^{4}(7 {m}^{3} n)  }{3 {m}^{5} {n}^{4}(9)  }  =  \frac{7 {m}^{3}n }{9}

___o___o___

<u>11. Ans;</u>

\frac{ - 15 {x}^{5}  {y}^{4} }{45x {y}^{3} }  =  \frac{ 15x {y}^{3} ( -  {x}^{4} y)}{15x {y}^{3}(3) }  =  -  \frac{ {x}^{4}y }{3}

___o___o___

<u>12.Ans;</u>

\frac{7 {p}^{2}  {q}^{2} }{14 {p}^{2} {q}^{2}  }  =  \frac{7 {p}^{2} {q}^{2}  }{7 {p}^{2} {q}^{2} (2) }  =  \frac{1}{2}  = 0.5

I hope I helped you^_^

7 0
3 years ago
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