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Anit [1.1K]
3 years ago
7

You are given the following functions: g(x) = x^2 + 4x + 5 and h(x) = 3x - 4 What is (g+h)(x)

Mathematics
1 answer:
Tasya [4]3 years ago
3 0

Answer:

g(x) = x² + 4x + 5

h(x) = 3x - 5

To find (g+h)(x) add h(x) to g(x)

That's

(g+h)(x) = x² + 4x + 5 + 3x - 4

Group like terms

(g+h)(x) = x² + 4x + 3x + 5 - 4

Simplify

We have the final answer as

<h2>(g+h)(x) = x² + 7x + 1</h2>

Hope this helps you

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What are the zero(s) of the function f(x)=<img src="https://tex.z-dn.net/?f=%5Cfrac%7B4x%5E%7B2%7D-36x%20%7D%7Bx-9%7D" id="TexFo
Contact [7]

Answer:

D

Step-by-step explanation:

The function will be zero when the numerator is equal to 0. So, set the numerator equal to 0 and solve:

0 = 4 {x}^{2}  - 36x

I will use the quadratic formula:

\frac{ 36  +  \sqrt{ {36}^{2}  - 4(4)(0)} }{2(4)}  \\  \frac{  36 + 36}{8}  = 9

Therefore, x = 9 is a 0. Let's check with subtracted root now:

\frac{ 36   -    \sqrt{ {36}^{2}  - 4(4)(0)} }{2(4)}  \\  \frac{ 36  -  36}{8}  =  0

It appears 0 is also a root.

Therefore, the answer is D.

7 0
3 years ago
Height of student folliwing normal distribution with a mean 170 cm and standard deviation of 5 cm. What is range of values conta
Gekata [30.6K]
I say 34 do not know if it is right
6 0
3 years ago
If a =-2 and b= 2 what will be the value of a^b
raketka [301]
Write out the equation;

y=a^b 
y=(-2)^2 
y=(-2)(-2) 
y=4 

Therefore, the value of a^b is 4 

Hope I helped :) 
7 0
3 years ago
Read 2 more answers
Pleases show workkkkkkkkkkkkkkkk
melomori [17]

Answer:

5) 2(4 - n) = -3n

2 × 4 - 2 × n = -3n

8 - 2n = -3n

-2n + 3n = -8

1n = -8

n = -8/1

n = -8

6) 5 - 3(2 + 2w) = -7

5 - 3 × 2 + -3 × 2w = -7

5 - 6 - 6w = -7

-1 - 6w = -7

-6w = -7 + 1

-6w = -6

w = -6/-6

w = 1

7) 5(2r + 3) - 5 = 0

5 × 2r + 5 × 3 - 5 = 0

10r + 15 - 5 = 0

10r + 10 = 0

10r = -10

r = -10/10

r = -1

8) 3 - 5(2d - 3) = 4

3 - 5 × 2d - 5 × -3 = 4

3 - 10d + 15 = 4

-10d + 15 + 3 = 4

-10d + 18 = 4

-10d = 4 - 18

-10d = -14

d = -14/-10

d = 7/5

hope this helps you!!

7 0
3 years ago
The floor of a rectangular meeting room is the same length as the room and is 1/6 the width of the room. What is the width of th
Arada [10]

Length of floor = length of room = 7.5 units

Width of floor = \frac{1}{6} * Width of Room = \frac{1}{6} * \frac{32}{5}

⇒ Width of floor = 1.067 units

3 0
3 years ago
Read 2 more answers
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