Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate
L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
I don't know, I just need points
lol
Answer:
A
Step-by-step explanation:
y = -9 ------(1)
9x -4y = -9 -------(2)
substitute (1) into (2)
9x - 4 (-9) = -9
9x = - 45
x = -5
there you go, x = -5 and y = -9
so. (-5 , -9 )
hope this helps
please mark it brainliest
Answer:
Step-by-step explanation:
When you have four terms and 3rd degree equation (the highest power is 3) you will want to try to "factor by grouping"
Group together two terms, watch out for the negative signs!
x^3 + 2x^2-5x-10=0
(x^3 + 2x^2) - (5x+10)=0
Find a common factor in each group and factor it out. You're hoping that what is left in the parenthesis is the same in both cases.
x^2(x+2)-5(x+2)=0
Now you can factor out that (x+2) because it is both terms.
x^2(x + 2) - 5(x + 2)=0
~~~~ ~~~~
Pull these out.
What will be left is the x^2 and the - 5 (dont lose that - in front of the 5)
(x + 2)(x^2 - 5) = 0
If all you have to do is factor, then you're done. It is factored. But if you have to "solve" also, then put x+2=0 and x^2-5=0 and solve.
x = -2 and x = +- sqrt5
The answer would be X =90
