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Anarel [89]
4 years ago
7

A cat rescue service found homes for 40 cats in 5 weeks. What was the rate of cats being placed per week? Which ratio is equal t

o the weekly rate?
A)
8 cats
1 week
; 24: 3
B)
1 cat
8 weeks
; 6 : 48
C)
4 cats
2 weeks
; 12 : 6
D)
16 cats
3 weeks
; 16 : 3
Mathematics
2 answers:
ExtremeBDS [4]4 years ago
7 0
A. 8 cats per week. if you simplify 40/5, it equals 8/1
miss Akunina [59]4 years ago
3 0

Answer:

It would be 8 cats per 1 week.

Step-by-step explanation:

The reason why i say this is because to find the rate, you have to figure out how many cats would fit into 1 week. So what you have to do is divide 5 by 40 and you get 8 cats within one week.

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A multiple-choice test contains 10 questions. there are four possible answers for each question. (a) in how many ways can a stud
devlian [24]
A). 4^10 = 1,048,576 ways

b). 5^10 = 9,765,625 ways
5 0
3 years ago
The morning announcements said that two out of every seven sixth-grade students in the school have an overdue library book. Jasm
gregori [183]

Answer:

We need to know how many students are in sixth grade and compare the real number with the 84 sixth graders that Jasmine claims to be.

Step-by-step explanation:

We would need to know how many students are in sixth grade to determine who is right. If two students out of seven have an overdue library book and grace claims that 24 of them are overdue by that means, what we would need to do is divide the allegedly 24 students between 2. Now we have 12 pairs of students that have overdue books. For every pair of students in sixth grade that have overdue books, seven students don’t have overdue books, so now we multiply 12 pairs of students with overdue books times 7 students who don’t have overdue books. By Jasmine calculation then, sixth grade have 84 students.  

If sixth grade have indeed 84 students, Jasmine is right. If there are not 84 students in sixth grade, she is wrong. Grace is right if there are fewer students than 84 in sixth grade.

Have a nice day! :D

6 0
3 years ago
How do you evaluate the trig expression sin(180°)?
d1i1m1o1n [39]
I'm pretty sure you can only do it by calculator
Press the SIN button, open parentheses, 180, close parentheses,
And hit enter
Hope this helps :)
3 0
3 years ago
Amy has $1,000 in a savings account at the beginning of the fall. She wants to have at least $500 in the account by the end of t
LuckyWell [14K]

Answer:

D. 1000 - 100w \geq 500; w \leq 5

Step-by-step explanation:

Given:

Initial amount in the bank = $1000

Money withdrawn each week = $100

Final amount should be at least $500.

Now, let the number of weeks the money is withdrawn be 'w'.

Therefore,

Money withdrawn in 'w' weeks = \textrm{Money withdrawn each week}\times w

Total Money withdrawn in 'w' weeks = 100w

Now, final amount after 'w' weeks is equal to the difference between initial amount and total withdrawal amount. Therefore,

Final amount = Initial amount - Total withdrawal amount

Final amount = 1000 - 100w

Now, final amount must be greater than or equal to $500. So,

\textrm{Final amount}\geq500\\\\1000-100w\geq500

Therefore, the  inequality that represents the inequality for the number of weeks Amy can withdraw money is:

1000-100w\geq500

Now, let us solve for 'w'.

Adding -500 and 100w both sides, we get:

1000-500-100w+100w\geq500-500+100w\\\\500\geq100w\\\\\textrm{The above inequality is reversed when taking 100w on the left side}\\\\100w\leq500\\\\w\leq\frac{500}{100}\\\\\therefore w\leq5

Therefore, the correct option is (D).

7 0
3 years ago
Read a system of equations to describe the situation below solve using illumination and fill in the blanks
Lana71 [14]

System of Equations

Let:

x = number of people that can be seated at a table

y = number of people that can be seated at a booth

The first plan consists of 23 tables and 10 booths and then 228 people could be seated, thus:

23x + 10y = 228

The second plan consists of 12 tables and 12 booths and that way 180 people could be seated, thus:

12x + 12y = 180

The method of elimination requires equating the coefficients of one variable and eliminating it by adding the equations.

Multiply the first equation by 12:

276x + 120y = 2736

Multiply the second equation by -23:

-276x - 276y = -4140

Add the last two equations (the variable x cancels out):

120y - 276y = 2736 - 4140

Simplifying:

-156y = -1404

Dividing by -156:

y = -1404/(-156)

y = 9

Substitute this value in the first equation:

23x + 10(9) = 228

Operate:

23x + 90 = 228

Subtract 90:

23x = 138

Divide by 23:

x = 138/23

x = 6

Every table can seat 6 people, and every booth can seat 9 people

4 0
1 year ago
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