Answer: Bottom and top (or which ever one is the small box in the middle and the one that looks like the small box in the middle)
Step-by-step explanation: the middle rectangle is the bottom and the other one like it is the top. the length is 7 in. and the height is 4 in. and 4 in. times 7 in. is 28in^2
DONT open file it’s a scam and tracker please don’t open it
Answer:
The set of coefficients asociated with the given polynomial in ascending order is ![[C] = \{4,0,5\sqrt{3}\}](https://tex.z-dn.net/?f=%5BC%5D%20%3D%20%5C%7B4%2C0%2C5%5Csqrt%7B3%7D%5C%7D)
.
Step-by-step explanation:
Let 
, which is a polynomic function, defined as:
(1)
Where:
- i-th Coefficient.
- i-th Power.
- Grade of the polynomial.
We notice that given polynomial has degree 2 and can be rewritten by applying this definition:
Then, the set of coefficients asociated with the given polynomial in ascending order is:
Answer:
<h3>
ln (e^2 + 1) - (e+ 1)</h3>
Step-by-step explanation:
Given f(x) = ln and g(x) = e^x + 1 to get f(g(2))-g(f(e)), we need to first find the composite function f(g(x)) and g(f(x)).
For f(g(x));
f(g(x)) = f(e^x + 1)
substitute x for e^x + 1 in f(x)
f(g(x)) = ln (e^x + 1)
f(g(2)) = ln (e^2 + 1)
For g(f(x));
g(f(x)) = g(ln x)
substitute x for ln x in g(x)
g(f(x)) = e^lnx + 1
g(f(x)) = x+1
g(f(e)) = e+1
f(g(2))-g(f(e)) = ln (e^2 + 1) - (e+ 1)
