Answer:
No real solution- Not any of the options anyway
Step-by-step explanation:
So I replaced the x's with the two possible equations and then tried to solve...
2=4+(4x2-4)1/2
2=4+(8-4)1/2
2=4+(4)1/2
2=8(1/2)
2=4 Which is not true
10=4+(4x10-4)1/2
10=4+(40-4)1/2
10=4+36(1/2)
10=40(1/2)
10=20 Which is also not true
Therefore, there is no real solution
10, ten is the gcf that’s your answer.
Answer:
see the explanation
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
m∠PQS+m∠SQR=m∠PQR ----> equation A (by Addition Angle Postulate)
we have that
m∠PQR=90° ----> equation B given problem (because is a right angle)
substitute equation B in equation A
m∠PQS+m∠SQR=90°
Remember that
Two angles re complementary is their sum is equal to 90 degrees (Definition of complementary angles)
therefore
m∠PQS and m∠SQR are complementary angles
Answer:
A would be 150 times.
Step-by-step explanation:
I can't see the options for Part B so i cant help with that sorry. I think A would be 150 times though because with numbers 1-10, half of them are even and half of them are odd and half of 300 is 150.
it would be 0 as its a 0 slope, hence forth the parallel line would also be 0!
