Third term = t3 = ar^2 = 444 eq. (1)
Seventh term = t7 = ar^6 = 7104 eq. (2)
By solving (1) and (2) we get,
ar^2 = 444
=> a = 444 / r^2 eq. (3)
And ar^6 = 7104
(444/r^2)r^6 = 7104
444 r^4 = 7104
r^4 = 7104/444
= 16
r2 = 4
r = 2
Substitute r value in (3)
a = 444 / r^2
= 444 / 2^2
= 444 / 4
= 111
Therefore a = 111 and r = 2
Therefore t6 = ar^5
= 111(2)^5
= 111(32)
= 3552.
<span>Therefore the 6th term in the geometric series is 3552.</span>
Add the gain and the last weight together
new weight = 6 3/4 + 1 1/2
or we can write it as
new weight = 6 + 3/4 + 1 + 1/2
Separate whole numbers and fraction
new weight = 6 + 3/4 + 1 + 1/2
new weight = 6 + 1 + 3/4 + 1/2
Simplify the whole numbers
new weight = 6 + 1 + 3/4 + 1/2
new weight = 7 + 3/4 + 1/2
Equalize the denominators of the fraction
new weight = 7 + 3/4 + 1/2
new weight = 7 + 3/4 + 2/4
new weight = 7 + 5/4
Because 5/4 is improper fraction, change it to mixed fraction
new weight = 7 + 5/4
new weight = 7 + 1 1/4
new weight = 7 + 1 + 1/4
new weight = 8 + 1/4
new weight = 8 1/4
The cat weights 8 1/4 pounds now
Answer: 22
explanation: the easiest way is to separate one of the diagonals into a triangle and use the pythagorean theorem.
a^2 + b^2 = c^2
4^2 + 3^3 = c^2
16 + 9 = c^2
25 = c^2
5 = c
you now know that both of the diagonals have a length of 5.
by counting the units on the two straight, you know that their length is 6.
6 + 6 + 5 + 5 = 22
5x⁴ - 3x³ + 6x) - (3x³ + 11x² - 8x)<span>
</span>Expand the second bracket by multiplying throughout by -1
5x⁴ - 3x³ + 6x - <span>3x³ - 11x² + 8x
</span>
Group like terms and simplify
5x⁴ - 3x³ - 3x³ - 11x² + 6x <span>+ 8x
</span>5x⁴ - 6x³ - <span>11x² + 14x</span>
Balls are good that’s the answer
