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dolphi86 [110]
3 years ago
14

Find the equation of the line in slope-intercept form.

Mathematics
2 answers:
photoshop1234 [79]3 years ago
7 0

Answer:

y=-2x+7

Step-by-step explanation:

............ ........

ivann1987 [24]3 years ago
4 0

Answer: y= -2x + 7

Step-by-step explanation: Slope intercept form is simply y=mx+b or y= slope(x) + y intercept.

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2. Solve the following equations for 0° Sx < 180°.
diamong [38]

Answer:

See below in bold.

Step-by-step explanation:

(1) cosec ( x + 10) = 3

Now cosec x = 1/sin x so

1 / sin (x + 10) = 3

3 sin (x + 10) = 1

sin (x + 10) = 1/3

x + 10 = 19.47 , 160.53 degrees

x = 9.47, 150.53 degrees.

(ii) cot (x - 30) =0.45

cot (x - 30)= 1 /tan (x- 30) so we have

tan (x - 30) = 1 / 0.45 = 2.2222

x - 30 = 65.77 degrees

x = 95.77 degrees.

5 0
3 years ago
Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes
azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

  • The centre of the ellipse is at the origin and the X axis is the major axis

  • It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

  • The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

Given that the ellipse passes through the point (-3, 1)

Hence,

\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1

Cross multiplying we get,

  • 9b² + a² = 1 ²× a²b²
  • a²b² = 9b² + a²

Multiply by 4 on both sides,

  • 4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1

Cross multiply,

  • 4b² + 4a² = 1 × a²b²
  • a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

  • 3a²b² = 32b²
  • 3a² = 32
  • a² = 32/3----(3)

Substituting in 2,

  • 32/3 × b² = 4b² + 4 × 32/3
  • 32/3 b² = 4b² + 128/3
  • 32/3 b² = (12b² + 128)/3
  • 32b² = 12b² + 128
  • 20b² = 128
  • b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1

\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
8 0
3 years ago
Leila works as a tutor for an hour and as a waitress for an hour. This month, she worked a combined total of hours at her two jo
kupik [55]

Answer:

E(t)  =  5t +672     ($)

Step-by-step explanation:     INCOMPLETE QUESTION

FROM GOOGLE

she earns 12 $ per hour as tutor and 7 $ per hour as waitress, this month she worked a combined of 96 hours at her two jobs

Let be t the numbers of hours Leila works as tutor this month

Answer:

If Leila worked t hours as tutor then, she worked (96 - t) hours as waitress

E(t)  =  12 * t  +  7 * (96-t)

E(t)  =  12t   +  672 - 7t

E(t)  =  5t +672     ($)

7 0
3 years ago
HELP DUE 8:30 will give brainliest
MariettaO [177]

The roots of the parabola is where the x-intercepts are so the answer is x=-1 and x= 5

5 0
3 years ago
$3000 is invested at 3% annual interest for 3 years.<br> a. Simple Interest b. Compound Interest
stich3 [128]

Answer:

a. $270

b. $3,278.18

Step-by-step explanation:

Given that

The principal amount is $3,000

Annual rate of interest is 3%

And, the time period is  3 years

We need to find out the simple interest & compound interest

The following formulas should be used

a. For simple interest

= Principal × rate of interest × time period

= $3,000 × 3% × 3 years

= $270

b. For compound interest

= Principal × (1 + rate of interest)^time period

= $3,000 × (1 + 0.03)3

= $3,000 × 1.03^3

= $3,278.18

8 0
2 years ago
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