Answer:
a) Alternative hypothesis should be one sided. Because Null and Alternative hypotheses are:
: μ=2.66 dyne-cm.
: μ<2.66 dyne-cm.
b) the hypothesis that mean adhesion is at least 2.66 dyne-cm is true
Step-by-step explanation:
Let μ be the mean adhesion in dyne-cm.
a)
Null and alternative hypotheses are:
: μ=2.66 dyne-cm.
: μ<2.66 dyne-cm.
b)
First we need to calculate test statistic and then the p-value of it.
test statistic of sample mean can be calculated as follows:
t=
where
- M is the mean adhesion assumed under null hypothesis (2.66 dyne-cm)
- s is the standard deviation known (0.7 dyne-cm_2)
Sample mean is the average of 2.69, 5.76, 2.67, 1.62 and 4.12 dyne-cm, that is
≈ 3.37
using the numbers we get
t=
≈ 2.27
The p-value is ≈ 0.043. Taking significance level as 0.05, we can conlude that sample proportion is significantly higher than 2.66 dyne-cm.
Thus, according to the sample the hypothesis that mean adhesion is at least 2.66 dyne-cm is true
Answer:
3.1 kilometers
Step-by-step explanation:
Mark me as brainliest if this helps!
Multiply -1 by -7
-9x^3 + 8x^2 - 7x/6 + 7
Answer:
A. square root of a^2 + b^2 for both answers
Step-by-step explanation:
The first problem, we are given
a^2 + b^2 = c^2
What we do is solve for c.
sqrt(a^2 + b^2) = c
c = sqrt(a^2 + b^2)
For problem 2,
WE can apply the Pythagorean theorem because we have a right triangle.
The equations is
a^2 + b^2 = c^2 like the first problem
Solving gets us
sqrt(a^2 + b^2) = c
c = sqrt(a^2 + b^2)
Answer:
Difference of squares:
y^4−25
16x^2−81
Not difference of squares:
20m^2n^2−121
p^8−q^5
Step-by-step explanation:
y^4−25
(y²)² - 5²
16x^2−81
(4x)² - 9²
20m^2n^2−121
20 is not a perfect square
p^8−q^5
q⁵ is not a perfect square