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spayn [35]
3 years ago
7

The table below shows how many triangles are formed when all the diagonals are drawn from one vertex in different regular polygo

ns. Based on the information in the table, which of the following statements is true? The number of triangles formed in any regular polygon is 2 less than the number of sides in the polygon. The number of triangles formed in any regular polygon is half the number of sides in the polygon. All the triangles formed in each regular polygon are congruent. All the triangles formed in each regular polygon are isosceles.
Mathematics
1 answer:
Scrat [10]3 years ago
3 0

Answer:

a

Step-by-step explanation:

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Please answer this question for me?
KIM [24]

Answer:

$16.96

Step-by-step explanation:

Do 3.99 times 2 to get 7.98

And then do 4.49 times 2 to get 8.98

Add the results together to get 16.96

3 0
3 years ago
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The variables y and x^2 are directly
choli [55]

Answer:

y = \frac{20}{21} x²

Step-by-step explanation:

Given that y and x² are directly proportional then the equation relating them is

y = kx² ← k is the constant of proportion

When x = 2

y = k × 2² = 4k

When x = 5

y = k × 5² = 25k

Then

25k - 4k = 20 ( difference between values is 20 )

21k = 20 ( divide both sides by 21 )

k = \frac{20}{21}

y = \frac{20}{21} x² ← equation of proportion

6 0
3 years ago
Let $f(x)$ be a function defined for all positive real numbers satisfying the conditions $f(x) > 0$ for all $x > 0$ and $f
algol [13]
Suppose we choose x=1 and y=\dfrac12. Then

f(x-y)=\sqrt{f(xy)+1}\implies f\left(\dfrac12\right)=\sqrt{f\left(\dfrac12\right)+1}\implies f\left(\dfrac12\right)=\dfrac{1+\sqrt5}2


Now suppose we choose x,y such that

\begin{cases}x-y=\dfrac12\\\\xy=2009\end{cases}


where we pick the solution for this system such that x>y>0. Then we find

\dfrac{1+\sqrt5}2=\sqrt{f(2009)+1}\implies f(2009)=\dfrac{1+\sqrt5}2

Note that you can always find a solution to the system above that satisfies x>y>0 as long as x>\dfrac12. What this means is that you can always find the value of f(x) as a (constant) function of f\left(\dfrac12\right).
3 0
3 years ago
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Solve the following equations for the unknown variable.
ser-zykov [4K]

Answer:

4

Step-by-step explanation:1.trust me

2.it will be it

3.just do it

7 0
3 years ago
∠A and \angle B∠B are supplementary angles. If m\angle A=(7x+10)^{\circ}∠A=(7x+10) ∘ and m\angle B=(7x-26)^{\circ}∠B=(7x−26) ∘ ,
blsea [12.9K]

Answer:

108 degrees

Step-by-step explanation:

Since angles A and B are supplementary, they both add up to 180. Angle A = 7x+10, and angle B = 7x-26. You can set up the equation A + B = 180, and then plug in angles A and B, which gives you 7x+10 + 7x-26 = 180. Then you just need to isolate x:

Combine like terms: 14x - 16 = 180

Add 16 to both sides: 14x = 196

Divide both sides by 14: x = 14

Now that you know x, you can plug it into the expression for angle A (7x+10):

A = 7(14) + 10 = 98+10 = 108

5 0
3 years ago
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