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bekas [8.4K]
3 years ago
11

From the figure and statement provided, select the proper TO PROVE statement. Through a point outside a line one line can be dra

wn parallel to the line. AB = BC MN = AB a is parallel to b AB + BC = AC m is parallel to l Please help
Mathematics
1 answer:
Readme [11.4K]3 years ago
4 0

Answer:

m is parallel to i

Step-by-step explanation:

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Please help me!! You must be good in math.
ivolga24 [154]
It is SAS because
1) it is given that sides are equal (AB=CD)
2)it is also given that angles B and C are equal
3) BC is a common side so it is equal in both triangles.

answer: SAS
8 0
3 years ago
Can someone please help me with these questions? I’m desperate! As always, I will give brainliest . I promise.
professor190 [17]

Since the centre of dilatation is the origin, we only require to multiply each of the coordinate points by the scale factor 3

(- 2, 1 ) → ( - 6, 3 )

(- 2, 3 ) → (- 6, 9 )

(1, 2 ) → (3, 6 )

(1, 3 ) → (3, 9 )



5 0
3 years ago
What is the Y intercept in the equation Y equals 45X +65?
VashaNatasha [74]
The typical form of the slope intercept equation would be:

Y = mX + B

Where b is the y intercept, thus in thus case the y intercept would be 65 = (0,65).
3 0
4 years ago
Douglas bought a $20 game card at a
satela [25.4K]

Answer:

Douglas can race the go-karts at least 3 times.

Step-by-step explanation:

Given that:

Worth of game card = $20

Cost of go-kart = $3.50 each time

Amount Douglas wants to left = $7.75

Let,

x be the times Douglas can ride go-kart.

20 - 3.50x ≤ 7.75

-3.50x ≤ 7.75 - 20

-3.50x ≤ -12.25

3.50x ≤ 12.25

Dividing both sides by 3.50

\frac{3.50x}{3.50}\leq \frac{12.25}{3.50}\\x\leq 3.5

Hence,

Douglas can race the go-karts at least 3 times.

5 0
3 years ago
ANSWER NEEDED ASAP!According to the table below, what is the probability that the age of a student chosen at random will be 15 o
saveliy_v [14]

The correct answer is C) 0.56

Explanation:

In general terms, the probability of two or more events can be calculated by adding the probability of each event. This rule applies when an event is considered as mutually exclusive. Age is considered as a mutually exclusive event because if a random individual is selected he/she will be only one age. In this context, if you need to know the probability that a student is 15 or younger it is necessary to add the probability that a student is 15, the probability that the student is 14, and the probability that the student is 13. The process is shown below:

P (A or B or C) = P(A) + P(B) + P(C)

P =  P(13) + P(14) + P(15)

P= 0.001 + 0.25 + 0.30

P= 0.56

8 0
3 years ago
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