The lowest grade he could earn is 120% of the grade at the end of the semester.
The following statement is given:
I have 90% after about 75% of the semester.
We are asked to find the lowest grade by the end of this semester.
<h3>What is Percentage?</h3>
A percentage is a number expressed as a fraction of 100.
- 50% = 50/100 = 1/2
- 25% = 25/100 = 1/4
- 20% = 20/100 = 1/5.
We can write this statement "I have a 90% grade after about 75% of the semester" as:
90% grade = 75% semester.............(1)
By the end of the semester means at 100% semester.
Multiplying equation (1) by 100/ 75 on both sides of the equation.
We get,
(100/75) x 90% grade = (100/75) x 75% semester
(100 x 90)/75 % grade = 100% semester
120% grade = 100%
Thus the lowest grade he could earn is 120% of the grade at the end of the semester.
Learn more about Percentages here:
brainly.com/question/24159063
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The last one y>-4
I hope this right
<u>Given</u><u> </u><u>:</u><u>-</u>
- Line p has an equation of y = 5/3x - 4 .
- Line q includes point (-10,-3) and is perpendicular to the line p .
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
<u>Solution</u><u> </u><u>:</u><u>-</u>
The equation of the line p is ,
y = 5/3x - 4
On comparing to slope intercept form of the line which is y = mx + c , we have ,
m = 5/3
Now as we know that the product of slopes of two perpendicular lines is -1 . So the slope of the perpendicular line will be ,
Now here the line q passes through the point (-10,-3) . So on using the point slope form of the line we get ,
y - (-3) = -3/5[ x-(-10)]
y +3 = -3/5(x+10)
y+3 = -3/5x - 6
y +9 = -3/5x
y = - 3/5x - 9
<u>Hence</u><u> the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>y </u><u>=</u><u> </u><u>-</u><u>3</u><u>/</u><u>5</u><u>x</u><u> </u><u>-</u><u> </u><u>9</u><u> </u><u>.</u>
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We know that :
If f(x) and g(x) are Two Functions Defined under same Domain, then Composite Function : (f o g)(x) = f(g(x))
Given : f(x) =
and g(x) = 
⇒ (f o g)(x) = f(g(x))
⇒ 
⇒ 
1st Option is the Answer