Question

What is the equation in point-slope form of the line passing through (3, 6) and (−2, 1)?

Answer 1

The point-slope form:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (3, 6) and (-2, 1). Substitute:

$m=\dfrac{1-6}{-2-3}=\dfrac{-5}{-5}=1\\\\y-6=1(x-3)$

Answer: 4. y - 6 = 1(x - 3)