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jeka57 [31]
3 years ago
14

Oil spill spreads 25 m² every 1/6 hour how much area does the oil spill cover after two hours

Mathematics
2 answers:
Delvig [45]3 years ago
6 0
1/6 of an hour is 10 minutes because there are 60 minutes in an hour so 60/6=10
so it's 25m^2/10minutes
now just multiply 25 by 12 ( 12 lots of 10 minutes in 2 hours)
25*12=300
answer is 300m^2

hope this helped
kow [346]3 years ago
6 0
Hello! 

Given the stated problem of an oil spill spreading at a rate of 25m^2 per 1/6 of an hour, which is equal to 10min, and they want to know what the area coverage from the oil spill is after 2 hours.

If we know that the oil spill spreads at a rate of 25m^2 per 10min and they want the area after two hours or 120min we get;

Area spread rate(Area/time) * total time wanted = new area at the total time

In the problem it tells us the area spread rate and total time so we can just plug and chug at this point. So we have;

25m^2/10min * 120min = 300m^2 after 2 hours of spreading.

Hope this helps! Any questions please ask! Thank you!!


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Answer:

If you round the answer, you'll get 4000

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3 years ago
Hey all! This is the another one, pls show the working......
zhannawk [14.2K]

Answer:

Hi again, I'm here to answer!

The correct answers:

10. x = -7 2/3

11. x = 2

12. x = 3

Step-by-step explanation:

(x + 3)/2 = (x - 4)/5

(5x + 15)/10 = (2x - 8)/10

3x/10 = -23/10

x = -23/3

x = -7 2/3

(2x - 1)/3 = x/2

(4x - 2)/6 = 3x/6

x/6 = 2/6

x = 2

(3x + 1)/5 = 2x/3

(9x + 3)/15 = 10x/15

-x/15 = -3/15

x = 3

Hope this helped!

8 0
3 years ago
In an arithmetic sequence, a_17 = -40 and a_28 = -73. Please explain how to use this information to write a recursive formula fo
Vinvika [58]

An arithmetic sequence

a_1,a_2,a_3,\ldots,a_n,\ldots

is one in which consecutive terms of the sequence differ by a fixed number, call it <em>d</em>. This means that, given the first term a_1, we can build the sequence by simply adding <em>d</em> :

a_2=a_1+d

a_3=a_2+d

a_4=a_3+d

and so on, the general pattern governed by the recursive rule,

a_n=a_{n-1}+d

We can exploit this rule in order to write any term of the sequence in terms of the first one. For example,

a_3=a_2+d=(a_1+d)+d=a_1+2d

a_4=a_3+d=(a_1+2d)+d=a_1+3d

and so on up to

a_n=a_1+(n-1)d

In this case, we're not given the first term right away, but the 17th. But this isn't a problem; we can use the same exploit to get

a_{18}=a_{17}+d

a_{19}=a_{17}+2d

a_{20}=a_{17}+3d

and so on, up to the next term we know,

a_{28}=a_{17}+11d=-40+11d

(Notice how the subscript of <em>a</em> on the right and the coefficient of <em>d</em> add up to the subscript of <em>a</em> on the left.)

The 28th term is -73, so we can solve for <em>d</em> :

-73=-40+11d\implies -33=11d\implies d=-3

To get the first term of the sequence, we use the rule found above and either of the known values of the sequence. For instance,

a_{17}=a_1+16d\implies-40=a_1-16\cdot3\implies a_1=8

Then the recursive rule for this particular sequence is

\begin{cases}a_1=8\\a_n=a_{n-1}-3&\text{for }n>1\end{cases}

7 0
3 years ago
What is the common difference between the terms in this arithmetic sequence?
nikdorinn [45]
They are adding 7 each time. The next would be 36+7 so it would be 43. :))
4 0
3 years ago
(5x2+10 to the third power)+10+7 show your work
balandron [24]
(5x2+10^3) +10+7 -> (10+1000) + 17 -> (1010) x 17 = 17,170
3 0
4 years ago
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