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meriva
3 years ago
7

Gilbert’s axioms changed Euclid’s geometry; true or false

Mathematics
1 answer:
Svetllana [295]3 years ago
5 0

Yes, Gilbert did it by identifying and explaining the concept of undefined terms.

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Jenny & Natasha are working on a problem together: Solve x/3 + 8 = −2. Natasha thinks the first step is to multiply by 3. Je
ratelena [41]

The individual that is correct is Natasha. This is because the answer can be gotten using Natasha's method

The given equation is  \frac{x}{3} + 8 = -2

<u><em>Solving the equation using </em></u><u><em>Natasha's</em></u><u><em> method </em></u>

the fist step is to multiply by 2

x + 24 = - 6

The second step is to combine  and add similar terms

x = -24 - 6

x = -30

<u><em /></u>

<u><em>Second method of solving the equation</em></u>

The equation the friends are trying to solve is \frac{x}{3} + 8 = -2

The first step is to combine similar terms

\frac{x}{3} = - 8 - 2

The second step is to add similar terms together

\frac{x}{3} = - 10

The third step is to multiply both sides of the equation by 3

x = (-10 x 3)

x = -30

A similar question was answered here: brainly.com/question/18613652?referrer=searchResults

5 0
3 years ago
The sum of a number and 8 is 15
kodGreya [7K]
You mean, what is this number?

we can rephrase it like this: the sum of a number x and 8 is 15

which is:

x+8=15

we subtract 8 from both sides and we get
x=7

so the answer is 7.
3 0
3 years ago
Read 2 more answers
F(x) ≥ -(x+4)^2<br>axis of symmetry: <br>vertex:
BlackZzzverrR [31]

Answer:

so the vertex is (-4, 0) and the axis of symmetry is x=-4

Step-by-step explanation:

f(x) ≥ -(x+4)^2

f(x) ≥ -(x- -4)^2

this is in the form

f(x)> a(x-h)^2 +k

where (h,k) is the vertex and h is the axis of symmetry

so the vertex is (-4, 0) and the axis of symmetry is x=-4

6 0
3 years ago
Use calculus to find the first order conditions. Use solver then to solve the first order conditions. Show your work for the fir
DaniilM [7]

The values of x and y are 70/22 and 30/22 respectively by using the first-order condition of differential calculus.

<h3>What is the first-order condition in differential calculus?</h3>

A first-order differential equation is represented by the equation \mathbf{ \dfrac{dy}{dx} =f (x,y) }with 2 variables x & y, including its function f(x,y) specified on a xy-plane.

Given that:

\mathbf{f(x,y) =-22x^2+22xy-11y^2+110x-40y-23}

Let us first differentiate the above equation with respect to x, we have:

\mathbf{\dfrac{\partial f(x,y) }{\partial x}  = -44x +22y -0+110-0-0=0}

\mathbf{\implies  -44x +22y+110=0}        (multiply by -1)

44x - 22y = 110    ------ (equation 1)

Now, differentiating with respect to y, we have:

\mathbf{\dfrac{\partial f(x,y) }{\partial y}  =0 +22x-22y +0-40-0=0}

\mathbf{\implies 22x-22y -40=0}

22x - 22y = 40      ----- (equation 2)

Now, we have a system of equations:

44x - 22y = 110

-                      ---- ( subtracting equation 2 from 1; elimination method)

<u> 22x - 22y = 40  </u>

<u>22x    + 0  = 70    </u>

<u />

x = 70/22

Replacing the value of x into equation (1), we have:

44x - 22y = 110

44(70/22) - 22y = 110

140 - 22y = 110

140 - 110 = 22y

30 = 22y

y = 30/22

Learn more about the first-order conditions in differential calculus here;

brainly.com/question/14528981

#SPJ1

4 0
2 years ago
Jared made some muffins. He wrote this equation to show the number of muffins in one batch. m = 8 Jared made 7 batches of muffin
sergeinik [125]
The correct answer would be C
7 0
4 years ago
Read 2 more answers
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