Answer:
13
Step-by-step explanation:
rounding 13.045 means look at the number in the tenths and hundreths place... it is 13
Answer:
![f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx-4%7D%20%2C%20g%28x%29%3D6x%5E%7B2%7D%5Ctextrm%7B%20or%20%7Df%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D%2Cg%28x%29%3D6x%5E%7B2%7D%20-4)
Step-by-step explanation:
Given:
The function, ![H(x)=\sqrt[3]{6x^{2}-4}](https://tex.z-dn.net/?f=H%28x%29%3D%5Csqrt%5B3%5D%7B6x%5E%7B2%7D-4%7D)
Solution 1:
Let ![f(x)=\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D)
If
, then,
![\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bg%28x%29%7D%20%3D%5Csqrt%5B3%5D%7B6x%5E%7B2%7D-4%7D%5C%5Cg%28x%29%3D6x%5E%7B2%7D-4)
Solution 2:
Let
. Then,
![f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3DH%28x%29%3D%5Csqrt%5B3%5D%7B6x%5E%7B2%7D-4%7D%5C%5C%5Csqrt%5B3%5D%7Bg%28x%29-4%7D%3D%5Csqrt%5B3%5D%7B6x%5E%7B2%7D-4%7D%20%5C%5Cg%28x%29-4%3D6x%5E%7B2%7D-4%5C%5Cg%28x%29%3D6x%5E%7B2%7D)
Similarly, there can be many solutions.
Answer:
5.000 ft
Step-by-step explanation:
The formula for the volume of a cylinder is
V = πr²h
Data:
V = 785.4 ft³
h = 2r
Calculations:
V = πr²h = πr²(2r) = 2πr³
Divide each side by 2π
Take the cube root of each side
![r = \sqrt[3]{\frac{V }{2\pi}}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7BV%20%7D%7B2%5Cpi%7D%7D)
![= \sqrt[3]{\frac{785.4 }{2\pi }}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B785.4%20%7D%7B2%5Cpi%20%7D%7D)
![= \sqrt[3]{125.00}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B125.00%7D)
= 5.000 ft
The radius of the cylinder is 5.000 ft.
First you to eliminate i from denominator.
mult by (7+3i) above and below
=(49+42i-9)/(49-9)
which is (40+42i)/40 which can simplify
Answer:
Step-by-step explanation:
The figure shows a circle with radius r сm. Another circle is drawn inside the circle such that its diameter is the radius of the original ...
answer
I think the answer would be 78.5 by Isaac Torres