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garri49 [273]
3 years ago
9

How would I graph the equation-6x +2y = -8?

Mathematics
1 answer:
ki77a [65]3 years ago
3 0

Answer:

Scroll down to see the graph using the link

Step-by-step explanation:

https://www.symbolab.com/solver/step-by-step/-6x%2B2y%3D-8

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I have 10 mins to turn this in... please help
marin [14]
Found this on socratic !!! hope this helps !!!!

5 0
2 years ago
Read 2 more answers
A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function
FinnZ [79.3K]

Answer:

The ball reaches a height of 29.25 ft after 1.125 seconds

Step-by-step explanation:

The maximum height of a parabola can always be found by looking for the vertex. You can find the x value (or in this case the t value) of a vertex by using -b/2a in which a is the coefficient of x^2 and b is the coefficient of x.

-b/2a

-(36)/2(-16)

-36/-32

1.125 seconds

Now to find the height, we input that value in for t

h = -16t^2 + 36t + 9

h = -16(1.125)^2 + 26(1.125) + 9

29.25 feet

6 0
3 years ago
Read 2 more answers
34
Vadim26 [7]

Answer:

They are similar by the definition of similarity in terms of a dilation

Step-by-step explanation:

The given vertices of triangle ΔABC are;

A(1, 5), B(3, 9), and C(5, 3)

The vertices of triangle ΔDEF are;

D(-3, 3), E(-2, 5), and F(-1, 2)

Therefore, we get;

The length of segment, \overline{AB} = √((9 - 5)² + (3 - 1)²) = 2·√5

The length of segment, \overline{BC} = √((9 - 3)² + (3 - 5)²) = 2·√10

The length of segment, \overline{AC} = √((5 - 3)² + (1 - 5)²) = 2·√5

The length of segment, \overline{DE} = √((5 - 3)² + (-2 - (-3))²) = √5

The length of segment, \overline{EF} = √((2 - 5)² + (-1 - (-2))²) = √10

The length of segment, \overline{DF} = √((2 - 3)² + (-1 - (-3))²) = √5

∴ \overline{AB}/\overline{DE} = 2·√5/(√5) = 2

\overline{BC}/\overline{EF} = 2·√10/(√10) = 2

\overline{AC}/\overline{DF} = 2·√5/(√5) = 2

The ratio of their corresponding sides are equal and therefore;

ΔABC and ΔDEF are similar by the definition of similarity in terms of dilation.

4 0
3 years ago
Which polynomial functions are written in
PolarNik [594]

Answer:

c and d

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Henri has $24000 invested in stocks and bonds. The amount in stocks is $6000 more than three times the amount in bonds. Call the
andrey2020 [161]

Answer:

Henri invested $ 4,500 in bonds and $ 19,500 in stocks.

Step-by-step explanation:

Given that Henri has $ 24000 invested in stocks and bonds, and the amount in stocks is $ 6000 more than three times the amount in bonds, to determine the amount that Henri invested in stocks (S) and the amount he invested in bonds (B), the following calculations must be performed:

6000 + 3B + B = 24000

3B + B = 24000 - 6000

4B = 18000

B = 18000/4

B = 4500

S = 6000 + 3x4500

S = 6000 + 13500

S = 19500

Thus, Henri invested $ 4,500 in bonds and $ 19,500 in stocks.

7 0
3 years ago
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