Considering the least common factor of 15 and 18, it is found that they will depart from the central station at the same time at 11 AM.
<h3>How to find the time it takes for periodic events to repeat at the same time?</h3>
To find the time that passes between the events happening at the same time, we need to find the least common multiple of the periods.
In this problem, the periods are of 15 and 18, hence their lcm is found as follows:
15 - 18|2
15 - 9|3
5 - 3|3
5 - 1|5
1 - 1
Hence:
lcm(15,18) = 2 x 3 x 3 x 5 = 90 minutes.
They will depart from the central station at the same time in 90 minutes from 9:30 AM, hence at 11 AM.
More can be learned about the least common factor at brainly.com/question/16314496
#SPJ1
Answer:
m∠PRT = 114°
m∠T = 37°
m∠RPT = 29°
Step-by-step explanation:
This question is incomplete (without a picture) ; here is the picture attached.
In this picture, an airplane is at an altitude 12000 feet.
When the plane is at the point P, pilot can observe two towns at R and T in front of plane.
We have to find the measure of ∠PRT, ∠T and ∠RPT.
Form the figure attached segment PS is parallel to RT and PR is a transverse.
We know that internal angles formed on one side of the parallel lines by a transverse are supplementary.
Therefore, x + 66 = 180
x = 180 - 66 = 114°
∠PRT = x = 114°
m∠RPT = m∠SPR - m∠SPT
= 66 - 37
= 29°
Since m∠PRT + m∠T + m∠RPT = 180°
114 + ∠T + 29 = 180
143 + ∠T = 180
∠T = 180 - 143
∠T = 37°
Answer:
(1,3) is the answer if this is question because you haven't given graph.
The answer is 1/14. -3/7 x -1/6. 3 crosses 6 2 time so you are left with -1/7 x -1/2 that is 1/14
2/7.
2/7 + 5/7 =1 Just add the numerator if the denominator is the same