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2 years ago

Round 68.321 to the nearest tenth

2 answers:

6 0

68.3 is the answer since each number after the decimal place has a name
For example: .1 = tenth, .11 = hundredth, .111 = thousandth, and so on

Lena [83]2 years ago

5 0

Answer:

When 68.321 rounded to the nearest tenth the result is 68

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Fine the value of X

makvit [3.9K]

Answer:

Step-by-step explanation:

60/40=3/2

105/40+x = 3/2

105/70=3/2

x=70-40 = 30

8 0

4 years ago

Read 2 more answers

Lydia inherited a sum of money. She split it into five equal parts. She invested three parts of the money in a high-interest ban

babunello [35]

I beileive he inherited 1,176.45 i tried to put my work on here but i couldnt find a way that it would make sense

3 0

3 years ago

Harry and Lisa Perry have agreed to pay for their granddaughter’s college education and need to know how much to set aside so an

Jobisdone [24]

Answer:

$117,836.49

Step-by-step explanation:

We can't make heads or tails of your table, so we have used a financial calculator to determine the multiplier is about 4.713. The calculator maintains more significant digits than that, so gives the value to the penny as ...

$117.836.49

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This value is about 4.71345951 × $25,000.

7 0

4 years ago

Maria compared the slope of the function f(x)=(-6x-21) to the slope of the linear function that fits the values in the table bel

raketka [301]

Answer:

b. both functions have a negative slope

Step-by-step explanation:

The given function is

$f(x)=-6x-21$

This function is of the form $y=mx+b$ , where $m=-6$ is the slope and $b=-21$ is the y-intercept.

We can also determine the slope of the function in the table using any two points, say $(0,7)\:and\:(2,6)$ .

The slope formula is given by,

$m=\frac{y_2-y_1}{x_2-x_1}$ .

If $(x_1,y_1)=(0,7)\:and\:(x_2,y_2)=(2,6)$ , then,

$m=\frac{6-7}{2-0}$

$m=-\frac{1}{2}$ .

We can see that both functions have a negative slope.

The correct answer is B.

8 0

3 years ago

In a missile-testing program, one random variable of interest is the distance between the point at which the missile lands and t

Arisa [49]

Answer:

Step-by-step explanation:

From the given data

we observed that the missile testing program

Y1 and Y2 are variable, they are also independent

We are aware that

$(Y_1)^2 and (Y_2)^2$ have $x^2$ distribution with 1 degree of freedom

and $V=(Y_1^2)+(Y_2)^2$ has x^2 with 2 degree of freedom

$F_v(v)=\frac{e^{-\frac{v}{2}}}2$

Since we have to find the density formula

$U=\sqrt{V}$

We use method of transformation

$h(V)=\sqrt{U}\\\\=U$

There inverse function is $h^-^1(U)=U^2$

We derivate the fuction above with respect to u

$\frac{d}{du} (h^-^1(u))=\frac{d}{du} (u^2)\\\\=2u^2^-^1\\\\=2u$

Therefore,

$F_v(u)=F_v(h-^1)(u)\frac{dh^-^1}{du} \\\\=\frac{e^-\frac{u^-^}{2} }{2} (2u)\\\\=e^-{\frac{u^2}{2} }U$

8 0

3 years ago