KE = 1/2(m * v^2)
KE = 1/2(1350 * 12^2)
KE = 1/2(1350 * 144)
KE = 1/2(194,400)
KE = 97,200 Joules
5)
a. The equation that describes the forces which act in the x-direction:
<span> Fx = 200 * cos 30 </span>
<span>
b. The equation which describes the forces which act in the y-direction: </span>
<span> Fy = 200 * sin 30 </span>
<span>c. The x and y components of the force of tension: </span>
<span> Tx = Fx = 200 * cos 30 </span>
<span> Ty = Fy = 200 * sin 30 </span>
d.<span>Since desk does not budge, </span><span>frictional force = Fx
= 200 * cos 30 </span>
<span> Normal force </span><span>= 50 * g - Fy
= 50 g - 200 * sin 30
</span>____________________________________________________________
6)<span> Let F_net = 0</span>
a. The equation that describes the forces which act in the x-direction:
(200N)cos(30) - F_s = 0
b. The equation that describes the forces which act in the y-direction:
F_N - (200N)sin(30) - mg = 0
c. The values of friction and normal forces will be:
Friction force= (200N)cos(30),
The Normal force is not 490N in either case...
Case 1 (pulling up)
F_N = mg - (200N)sin(30) = 50g - 100N = 390N
Case 2 (pushing down)
F_N = mg + (200N)sin(30) = 50g + 100N = 590N
The answer is b,
if you put them all in decimal form it would look like this:
-6.53, -6.25, 6.57, 6.75
The <em><u>correct answer</u></em> is:
At least 7 times.
Explanation:
Since 10% of the water in the jug is removed each time, this means that 100-10=90% of the water remains.
After two times, we would have 0.9(0.9) = 0.81 = 81% of the water; each time she pours, the number of times 0.9 is multiplied by itself changes. This makes this an exponential inequality (it is not an equation, as we want "less than half of the water"):
To solve this, we will use logarithms:
Answer:
There seriously is not enough information.
Step-by-step explanation:
