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morpeh [17]
2 years ago
6

I need help with my geometry test review.

Mathematics
1 answer:
Alexus [3.1K]2 years ago
3 0

Answer:

is that high school? cuz it looks like 8th or 7th grade

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Do f(x)and g(x) have the same y-intercept.
Amanda [17]

Answer:

Hmmmm

Step-by-step explanation:

Let’s see here

4 0
3 years ago
The annual rainfall (in inches) in a certain region is normally distributed with mean 43.2 and variance 20.8. Assume rainfall in
Wittaler [7]

Answer:

92.24% probability that out of 15 years, at most 2 have rainfall of more than 50 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the binomial probability distribution.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation(which is the square root of the variance) \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

\mu = 43.2, \sigma = \sqrt{20.8} = 4.56

Probability that a year has rainfall of more than 50 inches.

pvalue of Z when X = 50. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{50 - 43.2}{4.56}

Z = 1.49

Z = 1.49 has a pvalue of 0.9319

1 - 0.9319 = 0.0681

Find the probability that out of 15 years, at most 2 have rainfall of more than 50 inches.

This is P(X \leq 2) when n = 15, p = 0.0681. So

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{15,0}.(0.0681)^{0}.(0.9319)^{15} = 0.3472

P(X = 1) = C_{15,1}.(0.0681)^{1}.(0.9319)^{14} = 0.3805

P(X = 2) = C_{15,2}.(0.0681)^{2}.(0.9319)^{13} = 0.1947

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.3472 + 0.3805 + 0.1947 = 0.9224

92.24% probability that out of 15 years, at most 2 have rainfall of more than 50 inches.

8 0
3 years ago
Read 2 more answers
Is x-3/5 = N and N = 6, what is the value of x?
scZoUnD [109]

Answer:

x = 33/5

Step-by-step explanation:

x - 3/5 = n.......n = 6

so we sub

x - 3/5 = 6......add 3/5 to both sides

x = 6 + 3/5...convert using common denominator of 5

x = 30/5 + 3/5

x = 33/5 <===

check...

x - 3/5 = 6

33/5 - 3/5 = 6

30/5 = 6

6 = 6 (correct)...so it checks out

5 0
3 years ago
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Plzzzzzzzzz help thank u
Vikki [24]

Answer:

I think the answer is A

A is the answer

6 0
2 years ago
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Write a 10 digit number such that the first digit tells how many zeros there are in the entire number, the second digit tells ho
Dmitry [639]
6210001000
6 0s
2 1s
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