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Sergio [31]
3 years ago
5

Write a polynomial function that meets the given conditions. Answers may vary. Degree 2 polynomial with zeros of 2√ 13 and -2√13

Mathematics
1 answer:
MAVERICK [17]3 years ago
8 0

Answer:

The polynomial function is x^{2} - 52

Step-by-step explanation:

A polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}).

In this problem:

The roots are x_{1} = 2\sqrt{13} and x_{2} = -2\sqrt{13}

Then

(x - 2\sqrt{13}) \times (x - (-2\sqrt{13})) = (x - 2\sqrt{13}) \times (x + 2\sqrt{13}) = x^{2} - 2x\sqrt{13} + 2x\sqrt{13} -(2\sqrt{13})^{2} = x^{2} - 52

The polynomial function is x^{2} - 52

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Use the WeierstrassM-test to show that each of the following series converges uniformly on the given domain:
ryzh [129]

Answer:

Step-by-step explanation:

Given a series \sum_{k=1}^\infty f(z), the Weierstrass M-test tell us that if we find a sequence of positive numbers M_n such that |f(z)|\leq M_n in a certain domain D, and the series \sum_{n=1}^\infty M_k converges, then the series \sum_{k=1}^\infty f_k(z) converges uniformly in the domain D.

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Moreover, as z is in the interval [0,r], we have that z\leq r and as consequence |z^k|\leq r^k. With this in addition to the previous bound we obtain

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4 years ago
May I have some help?
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