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Sergio [31]
3 years ago
5

Write a polynomial function that meets the given conditions. Answers may vary. Degree 2 polynomial with zeros of 2√ 13 and -2√13

Mathematics
1 answer:
MAVERICK [17]3 years ago
8 0

Answer:

The polynomial function is x^{2} - 52

Step-by-step explanation:

A polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}).

In this problem:

The roots are x_{1} = 2\sqrt{13} and x_{2} = -2\sqrt{13}

Then

(x - 2\sqrt{13}) \times (x - (-2\sqrt{13})) = (x - 2\sqrt{13}) \times (x + 2\sqrt{13}) = x^{2} - 2x\sqrt{13} + 2x\sqrt{13} -(2\sqrt{13})^{2} = x^{2} - 52

The polynomial function is x^{2} - 52

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Quantos segundos tem 80 anos?
lara [203]

Answer:

2,522,880,000 segundos.

7 0
3 years ago
NEED HEELLLLPPPPPP!!
Tju [1.3M]
It looks equivalent.

Do the Pythagorean theorem on the triangle shown.
2.1^2-1.4^2

4.2-1.96=2.24

Sqrt of 2.24 is 1.496 or 1.5
Now multiply this by 2 to get the length of x

HOPE THIS HELPS
6 0
2 years ago
If f(x)=5x^2 and g(x)=x+1 find (f•g)
LenKa [72]

(f•g)=   f(1)•g(1)

= 5(1)^2 • (1)+1

= 5(1) • 2

= 5 • 2

= 10

Your answer here is 10.

Hope I helped!

8 0
3 years ago
Read 2 more answers
30-[11+{18-(48÷8×2)}+7]+15
Inessa05 [86]
30-(11+(18-(48/8×2))+7)+15

= 30-(11+(18-12)+7)+15

= 30-(11+6+7)+15

= 30-24+15

= 21
3 0
3 years ago
What are the zeros of the function<br><img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%202x%20%5E%7B2%7D%20-8x%20-%2010" id="Tex
allsm [11]
Hello there!

To find the zeroes or the roots of a function, you just need to set the function equal to 0 then solve for x

f(x) = 2x² - 8x - 10

Set function equal to 0

2x² - 8x - 10 = 0

Now we can factorize the left side

2(x + 1)(x - 5) = 0

Then set factors equal to 0

x + 1 = 0 or x - 5 = 0

x = 0 - 1 or x = 0 + 5

x = -1 or x = 5

Thus,

The roots are -1 and 5

Let me know if you have any questions. As always, it is my pleasure to help students like you~!
7 0
2 years ago
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