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2 years ago

3.25x+(-0.4y)+1/2 + 1/5y

Mathematics

1 answer:

romanna [79]2 years ago

6 0

Answer

3.25x − y/5 + 1/2

Step-by-step explanation:

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Can someone pls help me with this?

Misha Larkins [42]

Answer:

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Step-by-step explanation:

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2 years ago

If f(x) = x2 + x, find f(-3). -12 3 6

ANEK [815]

Answer:

-9

Step-by-step explanation:

-3(2) + (-3)

-6 + (-3)

-9

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2 years ago

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To bisect an angle using paper folding, fold the paper through the angle so that the line segments determining the angle lie:

algol [13]

To bisect an angle using paper folding, fold the paper through the angle so that the line segments determining the angle lie ON EACH OTHER.

To bisect means to divide into two equal parts and to find the middle line of the shape or angle. Simply fold the paper using the written lines of an angle. Each line must lie on each other, flatten the paper and the crease formed will be the bisecting line.

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3 years ago

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99 POINT QUESTION, PLUS BRAINLIEST!!!

Basile [38]

1.Disc method.
In this method the volume is given by:

$\boxed{V=\pi\int\limits_a^b\big[f(x)\big]^2}$

so:

$V=\pi\int\limits_1^3x^4\,dx=\boxed{\pi\int\limits_1^3\big[x^2\big]^2\,dx}$

A) Function $f(x)=x^2$ over the interval $[1,3]$
B) We use disk method and f(x) is function of variable x, so we rotate the curve about the x-axis.

2. Shell method.

In this case volume is given by:

 $\boxed{V=2\pi\int\limits_a^bx\cdot f(x)\,dx}$

So there will be:

$V=\pi\int\limits_1^3x^4\,dx=\dfrac{2}{2}\cdot\pi\int\limits_1^3x^4\,dx=2\pi\int\limits_1^3\dfrac{x^4}{2}\,dx=
\boxed{2\pi\int\limits_1^3x\cdot\dfrac{x^3}{2}\,dx}$

A) Function $f(x)=\dfrac{x^3}{2}$ over the interval $[1,3]$
B) We use shell method and f(x) is function of variable x, so we rotate the curve about the y-axis.

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2 years ago

An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est

nirvana33 [79]

Answer:

The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.8}{2} = 0.1$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.1 = 0.99$ , so $z = 1.28$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.28*\frac{4.1}{\sqrt{840}} = 0.2$

The lower end of the interval is the sample mean subtracted by M. So it is 40.6 - 0.2 = 40.4 words per minute.

The upper end of the interval is the sample mean added to M. So it is 40.6 + 0.2 = 40.8 words per minute.

The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.

3 0

3 years ago