Darius III.. he was the king of Persia at the time.
Answer:
The correct answer is A. Matilda recognizes her mother’s weakness.
Explanation:
Matilda's Mother's disclosure that "I didn't know if I was looking at a bad man or a man who loved me" made Matilda feel a little uneasy about being told such a thing, which she considers to be adult talk. However, it made her realize something and change her perception of her mother.
She realized that her mother is still stuck at an earlier period in her life where she suffered a disappointment from Matilda's father. Matilda realized that whatever it was that her father did is still stuck in her mother's head and she hasn't moved on from it.
The paragraph <em>Miss Havisham remains in her wedding gown for an event that has been and gone. I had an idea my mum was stuck in a similar moment. Only it had to do with an argument with my dad. Her frown gave her away. A frown that could be traced back to the original moment. I had an idea that whatever my dad had said still rang in her ears, </em>confirms that Matilda recognizes her mother's weakness of not being able to move on from what happened to her in the past.
Answer:
D
Explanation:
Because strength is a very strong word.
∵∴∵answer∵∴∵
Jenny
∵∴∵description∵∴∵
Jenny is the name given to a shrimping boat purchased by Forrest Gump from an old black shrimp fisherman, the first of the fleet of ships for the Bubba Gump Shrimp Company. He named it after the love of his life, Jenny Curran.
/.) (.\
/)\| |/(\
//)/ hope this helps -Tom \(\\
/'"^" "^"`\
I would like brainliest if I deserve it plz
Answer:
Gentoype of F1: all Bb
Phenotype of F1: black
Genotypes and phenotypes of F2:
1/4 BB - black fur
1/2 Bb - black fur
1/4 bb - brown fur
Explanation:
Black fur (B) is dominant over brown fur (b).
A true breeding black dog will have the genotype BB.
A true breeding brown dog will have the genotype bb.
If both of them are crossed:
BB x bb
F1 progeny: All Bb with Black fur.
At F2:
Bb x Bb
Progeny:
1 BB - black fur
2 Bb - black fur
1 bb - brown fur
<em>Hence:</em>
<em>Gentoype of F1 = all Bb</em>
<em>Phenotype of F1 = black</em>
<em>Genotypes and phenotypes of F2:</em>
<em>1 BB - black fur</em>
<em>2 Bb - black fur</em>
<em>1 bb - brown fur</em>
